Problem with lengh of string

[ricky]

I am reading the lines form the file and 'len' is returning the length
of each line.Now the problem is if i am not wrong windows uses carriage
return followed by a line feed to mark the end of the line. so for each
line 'len' should return be two extra characters ex. if i have file
gillian
dave
robby
so for gillian --it should return len 9(including \r\n according to
windows)
but the following function is returning 8. Is there anything wrong the
way i am doing it.

#include <fstream>
#include <istream>
#include <iostream>
#include <ostream>
#include <string>

using namespace std;
void omit(istream& in, ostream& out, const string s)
{
static string line;
int len;
while(getline(in,line))
{
len=line.length();
cout<<line<<endl;
cout<<len<<endl;
}
}

int main()
{
const string in_name("example.txt");
const string out_name("test.txt");

ifstream input(in_name.c_str());
ofstream output(out_name.c_str());

if(!input)
cerr << "Cannot open input\n";

if(!output)
cerr << "Cannot open output\n";

if(input && output)
omit(input, output, "raka");

if(!input.eof())
cerr << "Error reading input\n";

if(!output)
cerr << "Error writing output\n";

return 0;

}

[Victor Bazarov]

ricky wrote:

I am reading the lines form the file and 'len' is returning the length
of each line.Now the problem is if i am not wrong windows uses
carriage return followed by a line feed to mark the end of the line.
so for each line 'len' should return be two extra characters ex. if i
have file gillian
dave
robby
so for gillian --it should return len 9(including \r\n according to
windows)
but the following function is returning 8. Is there anything wrong the
way i am doing it.

You're opening your file with default mode, which is "text". You should
try opening it in "binary" mode. RTFM about those.

[..]

V
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[Eric Pruneau]

"ricky" <ri*******@yahoo.co.ina écrit dans le message de news:
11*********************@h48g2000cwc.googlegroups.c om...

>I am reading the lines form the file and 'len' is returning the length
of each line.Now the problem is if i am not wrong windows uses carriage
return followed by a line feed to mark the end of the line. so for each
line 'len' should return be two extra characters ex. if i have file
gillian
dave
robby
so for gillian --it should return len 9(including \r\n according to
windows)
but the following function is returning 8. Is there anything wrong the
way i am doing it.

getline extract characters until the delimiter is read.
Now the delimiter can be:
1. user specified (when using the optional third parameter of getline)
2. \n if no user specified parameter are used
3. end of file

the delimiter is extracted but NOT stored in the string
Eric