which is const in "char *const argv[]"

Eric

Hi
For this code,
int getopt (int argc, char *const argv[], const char *opts)
what does the "char *const argv[]" mean? Does it equal to "char **const
argv"?
Or "char *const *argv"? Which is the const?

Thanks

Jun 20 '06 #1

Michael Mair

Eric schrieb:

For this code,
int getopt (int argc, char *const argv[], const char *opts)
what does the "char *const argv[]" mean? Does it equal to "char **const
argv"?
Or "char *const *argv"? Which is the const?

char * const * argv.
I suggest that you get yourself a little programme called cdecl:
,---
$ cdecl
Type `help' or `?' for help
cdecl> explain char *const argv[]
declare argv as array of const pointer to char
cdecl> explain char *const *argv
declare argv as pointer to const pointer to char
`---
which of course is equivalent for function parameters

Cheers
Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.

Jun 20 '06 #2

John Bode

Eric wrote:

Hi
For this code,
int getopt (int argc, char *const argv[], const char *opts)
what does the "char *const argv[]" mean? Does it equal to "char **const
argv"?
Or "char *const *argv"? Which is the const?

Thanks

char * const * argv -- argv is a pointer to a const pointer to char;
essentially, argv is an array of const pointers.

Jun 20 '06 #3

lovecreatesbeauty

Michael Mair wrote:

I suggest that you get yourself a little programme called cdecl:

cdecl seems no much help, e.g.:

cdecl> explain void (*signal(int sig, void (*func)(int)))(int);
parse error
cdecl> explain int main(int argc, char *argv[]);
parse error
cdecl> explain int main(void);
declare main as function (void) returning int
cdecl>

lovecreatesbeauty

Jun 21 '06 #4

Harald van Dijk

lovecreatesbeauty wrote:

Michael Mair wrote:

I suggest that you get yourself a little programme called cdecl:

cdecl seems no much help, e.g.:

cdecl> explain void (*signal(int sig, void (*func)(int)))(int);
parse error
cdecl> explain int main(int argc, char *argv[]);
parse error
cdecl> explain int main(void);
declare main as function (void) returning int
cdecl>

cdecl doesn't properly support function prototypes. Its manpage tells
me that's because it was written before C89 was completed. Try it
without the parameter names:

cdecl> explain void (*signal(int, void (*)(int)))(int)
declare signal as function (int, pointer to function (int) returning
void) returning pointer to function (int) returning void

Jun 21 '06 #5

lovecreatesbeauty

Harald van Dijk wrote:

cdecl doesn't properly support function prototypes. Its man page tells
me that's because it was written before C89 was completed. Try it
without the parameter names:

Ok, following is the version information about cdecl on my Debian
Linux. Perhaps the year C89 was released is earlier than the year when
cdecl at 2.5 1/15/96. :)

$ pwd
/home/jhl/cdecl_2.5-6_i386
$ cdecl -V
Version:
@(#)cdecl.c 2.5 1/15/96
@(#)cdgram.y 2.2 3/30/88
@(#)cdlex.l 2.2 3/30/88
$

lovecreatesbeauty

Jun 21 '06 #6

Dik T. Winter

In article <11**********************@y41g2000cwy.googlegroups .com> "lovecreatesbeauty" <lo***************@gmail.com> writes:

Harald van D=C4=B3k wrote:

cdecl doesn't properly support function prototypes. Its man page tells
me that's because it was written before C89 was completed. Try it
without the parameter names:

.... Ok, following is the version information about cdecl on my Debian
Linux. Perhaps the year C89 was released is earlier than the year when
cdecl at 2.5 1/15/96. :)

$ pwd
/home/jhl/cdecl_2.5-6_i386
$ cdecl -V
Version:
@(#)cdecl.c 2.5 1/15/96
@(#)cdgram.y 2.2 3/30/88
@(#)cdlex.l 2.2 3/30/88
$

Probably a minor bugfix compared to:
@(#)cdecl.c 2.4 3/31/88
But note the date of cdlex (which does the parsing).

--
dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/

Jun 21 '06 #7

Eric

Uh ah, cdecl is really an interesting programme! Thanks.

Michael Mair wrote:

Eric schrieb:

For this code,
int getopt (int argc, char *const argv[], const char *opts)
what does the "char *const argv[]" mean? Does it equal to "char **const
argv"?
Or "char *const *argv"? Which is the const?

char * const * argv.
I suggest that you get yourself a little programme called cdecl:
,---
$ cdecl
Type `help' or `?' for help
cdecl> explain char *const argv[]
declare argv as array of const pointer to char
cdecl> explain char *const *argv
declare argv as pointer to const pointer to char
`---
which of course is equivalent for function parameters

Cheers
Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.

Jun 22 '06 #8