bitset woes

[Paul Richardson]

I have tried reading all the docs and I suppose I am just not parsing
them correctly so I'll ask here

suppose I have three bitsets as follows:
bitset<48> a;
bitset<48> b;
bitset<48> c:

I want to bit-by-bit and the contents of a and b and have them placed
in c, what does the syntax look like for this. I thought, given that
some of the operators are overloads, that i might look like

c = a &b

this does not work however
Thanks in advance

[stefan.ciobaca]

It works for me. I'm using g++

g++ (GCC) 3.4.6 (Gentoo 3.4.6-r1, ssp-3.4.5-1.0, pie-8.7.9)

to compile this

<code>
#include <bitset>
#include <iostream>

using namespace std;

int main()
{
bitset<48> a, b, c;

for (int i = 0; i < 48; ++i)
{
b[i] = rand() % 2;
a[i] = rand() % 2;
}
c = a & b;
cout << a << endl << b << endl << c << endl;
}
</code>

What compiler are you using? What exactly doesn't work?

Paul Richardson wrote:

I have tried reading all the docs and I suppose I am just not parsing
them correctly so I'll ask here

suppose I have three bitsets as follows:
bitset<48> a;
bitset<48> b;
bitset<48> c:

I want to bit-by-bit and the contents of a and b and have them placed
in c, what does the syntax look like for this. I thought, given that
some of the operators are overloads, that i might look like

c = a &b

this does not work however
Thanks in advance

[Paul Richardson]

Care to take on the usage of to_string()
On 2006-06-18 06:14:23 -0700, st************@gmail.com said:

It works for me. I'm using g++

g++ (GCC) 3.4.6 (Gentoo 3.4.6-r1, ssp-3.4.5-1.0, pie-8.7.9)

to compile this

<code>
#include <bitset>
#include <iostream>

using namespace std;

int main()
{
bitset<48> a, b, c;

for (int i = 0; i < 48; ++i)
{
b[i] = rand() % 2;
a[i] = rand() % 2;
}
c = a & b;
cout << a << endl << b << endl << c << endl;
}
</code>

What compiler are you using? What exactly doesn't work?

Paul Richardson wrote:

I have tried reading all the docs and I suppose I am just not parsing
them correctly so I'll ask here

suppose I have three bitsets as follows:
bitset<48> a;
bitset<48> b;
bitset<48> c:

I want to bit-by-bit and the contents of a and b and have them placed
in c, what does the syntax look like for this. I thought, given that
some of the operators are overloads, that i might look like

c = a &b

this does not work however
Thanks in advance

[ranchgirl]

I have not do C++ from sometime now, but I am back to the C++/C world for a new job.

Tried the above code, made a few modifications, everything seems fine, except the exclusive or get all zeros, don't know why.

Used gcc base compiler dev-c++.

Here is my code, please kindly find my possible errors. Thanks!

#include <bitset>
#include <iostream>
using namespace std;
#define SET_SIZE 32
int main() {
  bitset<SET_SIZE> a, b;
  bitset<SET_SIZE> c, d, e;
  for (int i=0; i<SET_SIZE; ++i) {
    b[i] = rand() % 2;
    a[i] = rand() % 2;
  }
  c = a & b;
  d = a | b;
  d = a ^ b;
  cout << a << endl << b << endl;
  cout << c << endl << d << endl << e << endl;
  cout << (3 ^ 4) << endl;
  system("pause");
}
 

a ranchgirl

[ranchgirl]

Sorry, ignore my post! I found I had a typo... :(