pointer to function as template parameter

[MaxMax]

I have a

template<class T, class TBase>
TBase* MyFunc(int *a, int *b)
{
T* pT = new T;
return static_cast<TBase*>(pT);
}

(the a and the b are used in some way in the true function)

(clearly TBase must be a base class of T to make it work)

I want to create something like

list<pointerfunctions> a;

How do I write the signature of the function? I can't use typedef because
there is a template...

--- Thanks

[Tomás]

MaxMax posted:

I want to create something like

list<pointerfunctions> a;

How do I write the signature of the function? I can't use typedef
because there is a template...

Please elaborate on the restriction -- I don't see any reason why you
couldn't use typedef.
list< void (*)() > a;
/* Or alternatively */

typedef void (*SimpleFunc)();

list< SimpleFunc > b;

-Tomás

[Cy Edmunds]

"MaxMax" <no**@none.com> wrote in message
news:%U********************@twister1.libero.it...

I have a

template<class T, class TBase>
TBase* MyFunc(int *a, int *b)
{
T* pT = new T;
return static_cast<TBase*>(pT);
Why the cast? pT is already a TBase*. And isn't this design likely to result
in memory leaks? This is mysterious stuff.
}
If you write

int a = 7;
int b = 12;
TBase *p = MyFunc(&a, &b);

how is the compiler supposed to figure out the type of T or TBase? (The type
of the return result cannot be used.)

I think a template class may be what you need but it is hard to be sure from
what you have given us.

(the a and the b are used in some way in the true function)

(clearly TBase must be a base class of T to make it work)

I want to create something like

list<pointerfunctions> a;
If you have a list of objects, they must all be of the same type. However,
they can be pointers (better yet smart pointers) to a common base class.
Again, this suggests you really want a polymorphic class rather than a
function here.

How do I write the signature of the function? I can't use typedef because
there is a template...

--- Thanks

[MaxMax]

> Please elaborate on the restriction -- I don't see any reason why you

couldn't use typedef.
list< void (*)() > a;
/* Or alternatively */

typedef void (*SimpleFunc)();

list< SimpleFunc > b;

Thanks a lot! I was finally able to do it! I had problems because I didn't
remember how the () and the (*) needed to be used.

--- bye