Can C++ allow multiple array assignment?

[Mr. Ken]

For example,
int arr[5];

arr = {1,2,3,4,5};

[Jonathan Mcdougall]

Mr. Ken wrote:

For example,
int arr[5];

arr = {1,2,3,4,5};

Next time, put your question in the message instead of in the subject.

No, this is not possible, except for initialization:

int arr[5] = {1,2,3,4,5}; // ok

You may consider using std::vector instead of arrays, they are more
versatile and safe, though they do not support this kind of assignment
either.
Jonathan

[Mr. Ken]

"Jonathan Mcdougall" <jo***************@gmail.com> wrote in message
news:11**********************@g10g2000cwb.googlegr oups.com...

Mr. Ken wrote:

For example,
int arr[5];

arr = {1,2,3,4,5};

Next time, put your question in the message instead of in the subject.

No, this is not possible, except for initialization:

int arr[5] = {1,2,3,4,5}; // ok

You may consider using std::vector instead of arrays, they are more
versatile and safe, though they do not support this kind of assignment
either.
Jonathan

Thank you Jonathan.
What I need is a one-liner to initialize arr into some values. will the
following code work?
int arr[5];
int dummy[5] = {1,1,1,1,1};

for (i = 0; i < 5; i = i + 1) {
*arr = dummy;
arr[i] = others;
// other codes involving array arr;
}

[Jonathan Mcdougall]

Mr. Ken wrote:

"Jonathan Mcdougall" <jo***************@gmail.com> wrote in message

Mr. Ken wrote:

For example,
int arr[5];

arr = {1,2,3,4,5};
Next time, put your question in the message instead of in the subject.

No, this is not possible, except for initialization:

What I need is a one-liner to initialize arr into some values. will the
following code work? int arr[5];
int dummy[5] = {1,1,1,1,1};

for (i = 0; i < 5; i = i + 1) {
Prefer:

for (int i=0; i<5; ++i)
*arr = dummy;
This is illegal, you are assigning an int* to an int.
arr[i] = others;
Well, depending on what 'others' is, it may or not be legal.
// other codes involving array arr;
}

I don't understand exactly what you are looking for. Please provide a
full example of what you are trying to accomplish.

Perhaps this?

# include <algorithm>

void f(int dummy[5])
{
int arr[5];
std::copy(dummy, dummy+5, arr);
}

Jonathan

[Mark P]

Mr. Ken wrote:

"Jonathan Mcdougall" <jo***************@gmail.com> wrote in message
news:11**********************@g10g2000cwb.googlegr oups.com...

Mr. Ken wrote:

For example,
int arr[5];

arr = {1,2,3,4,5};

Next time, put your question in the message instead of in the subject.

No, this is not possible, except for initialization:

int arr[5] = {1,2,3,4,5}; // ok

You may consider using std::vector instead of arrays, they are more
versatile and safe, though they do not support this kind of assignment
either.
Jonathan

Thank you Jonathan.
What I need is a one-liner to initialize arr into some values. will the
following code work?
int arr[5];
int dummy[5] = {1,1,1,1,1};

for (i = 0; i < 5; i = i + 1) {
*arr = dummy;
arr[i] = others;
// other codes involving array arr;
}

What is "others"? If you're trying to copy dummy to arr you can do the
following in one line:

std::copy(dummy,dummy+sizeof(dummy)/sizeof(*dummy),arr)

You'll also need to #include <algorithm>

cf. http://www.sgi.com/tech/stl/copy.html

[Mr. Ken]

int arr[5];
int dummy[5] = {1,1,1,1,1};

for (i = 0; i < 5; i = i + 1) {
Prefer:

for (int i=0; i<5; ++i)

*arr = dummy;

This is illegal, you are assigning an int* to an int.

Is this correct syntax?
arr = dummy;
// This assigns the base address of dummy to arr.
// Will "arr[i] = 2; " alter the content of dummy[i]?

arr[i] = others;
Well, depending on what 'others' is, it may or not be legal.

others = 200*i/123;

// other codes involving array arr;
}
I don't understand exactly what you are looking for. Please provide a
full example of what you are trying to accomplish.

What I need is, in each loop, the array is initialized to {1,1,1,1,1}, then
a few elements of the
array is altered. Subsequent codes will depend on the content of the array
to work properly.


Perhaps this?

# include <algorithm>

void f(int dummy[5])
{
int arr[5];
std::copy(dummy, dummy+5, arr);
}

Jonathan

Does std::copy work with old versions of gcc-2.95?

Thank you Jonathan.

[Mr. Ken]

>

What is "others"? If you're trying to copy dummy to arr you can do the
following in one line:

std::copy(dummy,dummy+sizeof(dummy)/sizeof(*dummy),arr)

You'll also need to #include <algorithm>

cf. http://www.sgi.com/tech/stl/copy.html

others are some integer values, thus "arr[i] = others;" alters the content
of a
an element.

The company's software are very outdated, does std::copy work with gcc-2.95
in Unix shell?

[Mark P]

Mr. Ken wrote:

What I need is, in each loop, the array is initialized to {1,1,1,1,1}, then
a few elements of the
array is altered. Subsequent codes will depend on the content of the array
to work properly.

If you really want all elements initialized to the same value then
std:vector has a constructor which does this.
Does std::copy work with old versions of gcc-2.95?

This I don't know. It would be easy to write a little program to test
it though.

[Jonathan Mcdougall]

Mr. Ken wrote:

int arr[5];
int dummy[5] = {1,1,1,1,1};

for (i = 0; i < 5; i = i + 1) {
Prefer:

for (int i=0; i<5; ++i)

*arr = dummy;

This is illegal, you are assigning an int* to an int.

Is this correct syntax?
arr = dummy;

No. You cannot assign arrays.
// This assigns the base address of dummy to arr.
// Will "arr[i] = 2; " alter the content of dummy[i]?
No, this makes no sense. Arrays are not pointers, pointers are not
arrays.

arr[i] = others;

Well, depending on what 'others' is, it may or not be legal.

others = 200*i/123;

Ok, I suppose others is [convertible to] an int.

// other codes involving array arr;
}

I don't understand exactly what you are looking for. Please provide a
full example of what you are trying to accomplish.

What I need is, in each loop, the array is initialized to {1,1,1,1,1}, then
a few elements of the
array is altered. Subsequent codes will depend on the content of the array
to work properly.

Just use a loop, it's simple and it works.
Does std::copy work with old versions of gcc-2.95?

Dunno, you should ask them. It probably does, although 2.95 is what, 10
years old?
Jonathan

[Mr. Ken]

"Jonathan Mcdougall" <jo***************@gmail.com> wrote in message
news:11*********************@u72g2000cwu.googlegro ups.com...

Just use a loop, it's simple and it works.

Does std::copy work with old versions of gcc-2.95?

Dunno, you should ask them. It probably does, although 2.95 is what, 10
years old?
Jonathan

Yeah, I am using a loop anyhow. In the manual, it says latest updated on
1993.

[red floyd]

Mr. Ken wrote:

"Jonathan Mcdougall" <jo***************@gmail.com> wrote in message
news:11*********************@u72g2000cwu.googlegro ups.com...

Just use a loop, it's simple and it works.

Does std::copy work with old versions of gcc-2.95?

Dunno, you should ask them. It probably does, although 2.95 is what, 10
years old?
Jonathan

Yeah, I am using a loop anyhow. In the manual, it says latest updated on
1993.

Unfortunately 2.95 (2.96, actually) is the version that VxWorks uses.

[Jonathan Mcdougall]

Mr. Ken wrote:

"Jonathan Mcdougall" <jo***************@gmail.com> wrote in message
news:11*********************@u72g2000cwu.googlegro ups.com...

Just use a loop, it's simple and it works.

Does std::copy work with old versions of gcc-2.95?

Dunno, you should ask them. It probably does, although 2.95 is what, 10
years old?
Jonathan

Yeah, I am using a loop anyhow. In the manual, it says latest updated on
1993.

Nice, were there keyboards at that time? :)
Jonathan