dynamic memory allocating

[filox]

i'm having a really hard time with this one:

class foo
{
private:
char* p;
public:
foo(int);
};
foo::foo(int j)
{
p = new char[j];
p[0] = '1';
p[1] = '2';
};
int main(void)
{
foo k(2);
return 0;
}
why can't i set the value of p[1]? p[0] passes ok, while p[1] = '2' is just
ignored.
please help
--
You're never too young to have a Vietnam flashback

[Bob Hairgrove]

On Mon, 24 Apr 2006 16:31:17 +0200, "filox"
<fi*****************@yahoo.com> wrote:

i'm having a really hard time with this one:

class foo
{
private:
char* p;
public:
foo(int);
};
foo::foo(int j)
{
p = new char[j];
p[0] = '1';
p[1] = '2';
};
int main(void)
{
foo k(2);
return 0;
}
why can't i set the value of p[1]? p[0] passes ok, while p[1] = '2' is just
ignored.
please help

What do you mean by "ignored"? Are you trying to create a C-style
string? If so, you will need to leave room for the null byte at the
end.

(BTW, you have a memory leak -- by not calling "delete [] p;" in the
destructor of your class or some other appropriate place).

--
Bob Hairgrove
No**********@Home.com

[filox]

uhm, never mind. there's actually no problem, i just put too much fait in Ms
Visual Studio debugger :)
its ok now. thanks for your effort, though

--
You're never too young to have a Vietnam flashback
"Bob Hairgrove" <in*****@bigfoot.com> wrote in message
news:5n********************************@4ax.com...

On Mon, 24 Apr 2006 16:31:17 +0200, "filox"
<fi*****************@yahoo.com> wrote:

i'm having a really hard time with this one:

class foo
{
private:
char* p;
public:
foo(int);
};
foo::foo(int j)
{
p = new char[j];
p[0] = '1';
p[1] = '2';
};
int main(void)
{
foo k(2);
return 0;
}
why can't i set the value of p[1]? p[0] passes ok, while p[1] = '2' is justignored.
please help

What do you mean by "ignored"? Are you trying to create a C-style
string? If so, you will need to leave room for the null byte at the
end.

(BTW, you have a memory leak -- by not calling "delete [] p;" in the
destructor of your class or some other appropriate place).

--
Bob Hairgrove
No**********@Home.com