address of return value

igor.lautar

Hi,

How can I get the address of return value in function?

ex.

int function(int argument)
{
int *arg_address;
int *rtn_address;

arg_address = &argument;
rtn_address = ??;

Mar 31 '06 #1

ytfrdfiw

may be,you can do as following:

int ss(int i)
{
int *k = &i;
int *j = &i;
return (int)j; //this is a cast,becase j is a type of
int*
}

Mar 31 '06 #2

ytfrdfiw

maybe,you can as following:
int ss(int i)
{
int *k = &i;
int *j = &i;
return (int)j; //this is a cast;

}

Mar 31 '06 #3

Alan Johnson

ig*********@gmail.com wrote:

Hi,

How can I get the address of return value in function?

It is not necessarily the case that the return value even has an
address. For sufficiently small types your compiler may choose to place
the return value in a register.

Alan

Mar 31 '06 #4

Bernd Strieder

Hello,

ig*********@gmail.com wrote:

How can I get the address of return value in function?

Plain and simple answer, you can't. The location of the return value is
completely in the hands of the compiler, whether register or stack or
whatever. There are no syntactical means for influencing the return
value location or taking its address.

This would be helpfull to print return value automatically (when
object is destroyed).

I don't understand this, maybe you could provide a more complete
example, what you want to achieve, especially what it has to do with
destruction of an object.
Bernd

Mar 31 '06 #5

海风

Getting an address of return value in function, why?

I think it's illegal, just silly.

The variable has been beyond its scope, but you want to use it by its'
pointer.

If i were you , I would never do that.

Mar 31 '06 #6

Maxim Yegorushkin

ig*********@gmail.com wrote:

Hi,

How can I get the address of return value in function?

Make the function take the address to store the return value into:

void f(int* result)
{
// here results is the address of the return value
*result = -1;
}

Mar 31 '06 #7

igor.lautar

Well, it would be usefull for tracing. Destructor of object would print
return value automatically (when object goes out of scope - at the
return from function).

You can always do:
int f(int a)
{
int ret = 0;
int *ret_addr = &ret;

Apr 1 '06 #8

dost

igor.....
do..u want to print..the address...of
variable...or....exact...locataion......of...retur n...value..location

Apr 1 '06 #9

igor.lautar

I want to print return value automatically, without doing cout on every
return. This could be done if one has address of return variable or
address of temporary variable (above example), which is always set to
return value before actually returning. Then create an temporary
object, which prints this value at destruction.

Hope its clearer now. Should have give more info to start with... My
bad.

Regards,
Igor

Apr 2 '06 #10

igor.lautar

I want to print return value automatically, without doing cout on every
return. This could be done if one has address of return variable or
address of temporary variable (above example), which is always set to
return value before actually returning. Then create an temporary
object, which prints this value at destruction.

Hope its clearer now. Should have give more info to start with... My
bad.

Regards,
Igor

Apr 2 '06 #11

Michiel.Salters

ig*********@gmail.com wrote:

I want to print return value automatically, without doing cout on every
return. This could be done if one has address of return variable or
address of temporary variable (above example), which is always set to
return value before actually returning.

How about a suitable #define RETURN?

As an added bonus, you can make it print only in debug mode.

HTH,
Michiel Salters

Apr 3 '06 #12