while and goto

[Jessica Weiner]

this loop will execute 5 times, correct?

for(i = 0; i < 10; i++)
{
if ( i == 5 )
goto end;
}

end:

[Noah Roberts]

Jessica Weiner wrote:

this loop will execute 5 times, correct?

for(i = 0; i < 10; i++)
{
if ( i == 5 )
goto end;
}

end:

6

[Alan Johnson]

Jessica Weiner wrote:

this loop will execute 5 times, correct?

for(i = 0; i < 10; i++)
{
if ( i == 5 )
goto end;
}

end:

It depends on what you mean. The body of the loop will be entered six
times. Any code added to the end of the loop body would be executed
five times (assuming it doesn't do anything to affect flow control).
Under either interpretation, I'd argue the loop is only executed once.

[sriram.sundararajan]

#include <iostream>
using namespace std;

int main(int argc, char* argv[])
{
for(int i=0; i<10; i++)
{
cout << i + 1 << endl;
if(i == 5)
goto end;
}
end:
cout << "Out of loop";
return 0;
}
Should give you the answer..

[ashwani]

It will display output as
1
2
3
4
5
6
Out of loop

[Vijay]

6

[Stewart Gordon]

Jessica Weiner wrote:

this loop will execute 5 times, correct?

Get yourself a C++ compiler and found out!

Stewart.

--
-----BEGIN GEEK CODE BLOCK-----
Version: 3.1
GCS/M d- s:-@ C++@ a->--- UB@ P+ L E@ W++@ N+++ o K-@ w++@ O? M V? PS-
PE- Y? PGP- t- 5? X? R b DI? D G e++>++++ h-- r-- !y
------END GEEK CODE BLOCK------

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