Hi all:
In the standuard 9.3.2, it says: The type of /this/ in a member function of a class X is X*. If the member
function is declared const, the type of /this/ is const X*, if the member
function is declared volatile, the type of /this/ is volatile X*, and if the
member function is declared const volatile, the type of this is const volatile X*.
IMO, the /this/ pointer can not be used as a l-value, so its type
should be X* const
instead of X*.(accordingly, const X* const instead of const X*,etc...)
Why the standuard "omit" that "const"?
(It's my first time to post on USENET. Hope me have not done any stupid
thing.)
Thanks,
FT
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FT wrote: In the standuard 9.3.2, it says: The type of /this/ in a member function of a class X is X*. If the
member function is declared const, the type of /this/ is const X*,
if the member function is declared volatile, the type of /this/ is
volatile X*, and if the member function is declared const volatile,
the type of this is const volatile X*.
IMO, the /this/ pointer can not be used as a l-value, so its type
should be X* const
instead of X*.(accordingly, const X* const instead of const
X*,etc...)
Why the standuard "omit" that "const"?
The beginning of the paragraph you quoted states that 'this' is
a non-lvalue expression. After defining 'this' as non-lvalue, there
is no need to claim that it's "const".
V
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FT wrote: IMO, the /this/ pointer can not be used as a l-value, so its type
should be X* const
instead of X*.(accordingly, const X* const instead of const X*,etc...)
Why the standuard "omit" that "const"?
'this' was invented before references. Consider 'this' as "not a pointer,
but a thing you write -> or * on".
'this' is as close to a reference as makes no difference.
You are correct the language of that Standard snip is incorrect. Yet because
'this' is not a pointer, the authors don't need to be accurate. Other
language doubtless covers "you cannot change 'this', take its address, etc."
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