overriding template function doesn't work?

[thinktwice]

template <class T>
class CThrowable
{
protected:
virtual void Assign(T val)
{
m_val = val;
if (IsBad())
{
throw val;
}
}
virtual bool IsBad() const
{
return false;
}
T m_val;
};

class CThrowableHRESULT : public CThrowable<HRESULT>
{
public:
CThrowableHRESULT(HRESULT val)
{
Assign(val);
}
protected:
bool IsBad()
{
return !SUCCEEDED(m_val);
}
};

class CThrowableBoolean : public CThrowable<bool>
{
public:
CThrowableBoolean(bool val)
{
Assign(val);
}
protected:
bool IsBad()
{
return !m_val;
}
};


CThrowableBoolean tBoolean(true);
tBoolean = false; //won't throw, actually it calls IsBad which is in
the base class ,why?
CThrowableHRESULT tHRESULT(S_OK);
tHRESULT = E_FAIL; //won't throw ,

[thinktwice]

another problem quite confuse me is
class CThrowableBoolean : public CThrowable<bool>
{
public:
CThrowableBoolean(bool val)
{
Assign(val);
}
/* if i comment this operator function when i call
tBoolean = false , it will call class construct
CThrowableBoolean(bool) , but if i open the operator= method , tBoolean
= flase will lead to call operator=(bool), is this the c++ standard
that c++ vendor should obey?
bool operator =(bool val)
{
Assign(val);
return m_val;
}
*/
protected:
bool IsBad()
{
return !m_val;
}
};

[Rolf Magnus]

thinktwice wrote:

CThrowableBoolean tBoolean(true);
tBoolean = false; //won't throw, actually it calls IsBad which is in
the base class ,why?
Because IsBad's signature in the base class is different from those in the
derived classes (const/non-const), so they are different functions.
CThrowableHRESULT tHRESULT(S_OK);
tHRESULT = E_FAIL; //won't throw ,

[thinktwice]

how careless am i!
but even if i fix this problem , it still call the method in the base
class

[Rolf Magnus]

thinktwice wrote:

another problem quite confuse me is
class CThrowableBoolean : public CThrowable<bool>
{
public:
CThrowableBoolean(bool val)
{
Assign(val);
}
/* if i comment this operator function when i call
tBoolean = false , it will call class construct
CThrowableBoolean(bool) , but if i open the operator= method , tBoolean
= flase will lead to call operator=(bool), is this the c++ standard
that c++ vendor should obey?
Well, what did you expect?
Without your assignment operator, there is only one assignment operator
available, and that is the compiler-generated one that takes a reference to
a CThrowableBoolean as right hand sid. So the compiler can only use that
one to do the assignment. Therefore, it will use the conversion constructor
to convert the bool on the right side to a CThrowableBoolean and then do
the assignment. If you add your assignment operator that takes a bool, the
compiler has an option that fits better, because no conversion is needed,
so it will choose that one.
bool operator =(bool val)
{
Assign(val);
return m_val;
}
*/
protected:
bool IsBad()
{
return !m_val;
}
};