Pointer assignment

[jasonbessette]

Say I have the following line:

Nothing *here = &doing;

My nothing class is just this:

class Nothing
{
};

I need to explicitly provide what the compiler implicitly provides. So
basically I need fill in my nothing class with the function that the
above line will call and I have no clue! I have the first three lines
in Main figured out, it's just the last two that I need help with. Here
is what I have so far with the other things for this class
Nothing.h ========================
class Nothing
{
public:
Nothing()
{
cout << "Executing the default constructor ========>" << endl;
}

Nothing(const Nothing&)
{
cout << "Executing the copy constructor ===================>" <<
endl;
}

Nothing& operator=(const Nothing &rhs)
{
cout << "Executing the assignment operator ================>" <<
endl;
return *this;
}
};

Nothing.cpp =========================================

#include "nothing.h"

int main()
{
const Nothing ness;

Nothing doing(ness);

doing = ness;

Nothing *here = &doing;
const Nothing *anywhere = &ness;

return 0;
}
-Jason

[ferdinand.stefanus]

ja***********@gmail.com wrote:

Say I have the following line:

Nothing *here = &doing;

My nothing class is just this:

class Nothing
{
};

I need to explicitly provide what the compiler implicitly provides. So
basically I need fill in my nothing class with the function that the
above line will call and I have no clue! I have the first three lines
in Main figured out, it's just the last two that I need help with. Here
is what I have so far with the other things for this class
Nothing.h ========================
class Nothing
{
public:
Nothing()
{
cout << "Executing the default constructor ========>" << endl;
}

Nothing(const Nothing&)
{
cout << "Executing the copy constructor ===================>" <<
endl;
}

Nothing& operator=(const Nothing &rhs)
{
cout << "Executing the assignment operator ================>" <<
endl;
return *this;
}
};

Nothing.cpp =========================================

#include "nothing.h"

int main()
{
const Nothing ness;

Nothing doing(ness);

doing = ness;

Nothing *here = &doing;
const Nothing *anywhere = &ness;

return 0;
}
-Jason

I'm not sure I get your intention here, but if you want the address-of
operator (&) to behave differently, you can always overload it, e.g.:

Nothing* operator&()
{
cout << "In address-of operator\n";
return this;
}