C99 struct initialization (C99/gcc)

[jilerner]

Question about C99/gcc struct initialization:

void ffoo(void) {
struct FOO { int a,b,c; };
struct foo = { .b = 22 };

What happens now to foo.a and foo.c ? Are they initialized to 0,
or left unitialized ?

Y.L.

[Emmanuel Delahaye]

ji******@yahoo.com a écrit :

Question about C99/gcc struct initialization:

void ffoo(void) {
struct FOO { int a,b,c; };
struct foo = { .b = 22 };
Handy, isn't it ?
What happens now to foo.a and foo.c ? Are they initialized to 0,
Yes.
or left unitialized ?

No.

--
A+

Emmanuel Delahaye

[Abhishek]

Thats one good thing you get with C99.

ji******@yahoo.com wrote:

Question about C99/gcc struct initialization:

void ffoo(void) {
struct FOO { int a,b,c; };
struct foo = { .b = 22 };

What happens now to foo.a and foo.c ? Are they initialized to 0,
or left unitialized ?

Y.L.

[Chris Torek]

(I saved this to reply to later, in case no one else did. I saw
no useful replies, so here is one.)

In article <11*********************@g43g2000cwa.googlegroups. com>
<ji******@yahoo.com> wrote:

Question about C99/gcc struct initialization:

void ffoo(void) {
struct FOO { int a,b,c; };
struct foo = { .b = 22 };
This is a syntax error. Presumably you mean:

struct FOO foo = { .b = 22 };
What happens now to foo.a and foo.c ? Are they initialized to 0,
or left unitialized ?

In C99, unmentioned members of an otherwise-initialized aggregate
are initialized to zero. So foo.a and foo.c are set to 0.

What GNUC does with them is off-topic. :-)
--
In-Real-Life: Chris Torek, Wind River Systems
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