Is this part of the standard?

[copx]

Is the "-" operator (meaning * (-1) ) part of the standard?

Example program:

#include <stdio.h>

int main(void)
{
int a = -5;

printf("%d", -a); /* should print 5 */

return 0;
}
Is that portable?

[loufoque]

copx a écrit :

Is the "-" operator (meaning * (-1) ) part of the standard?

Yes.

[Vladimir S. Oka]

copx wrote:

Is the "-" operator (meaning * (-1) ) part of the standard?
Yes (C&V 6.5.3). It's called "unary minus" (same as in maths, really).
Example program:

#include <stdio.h>

int main(void)
{
int a = -5;

printf("%d", -a); /* should print 5 */

return 0;
}
Is that portable?

No, as you did not terminate `printf` with '\n'. Not doing so makes it
possible for a conforming implementation to do anything, including not
printing out any characters at all. ;-)

As for a unary `-`, yes, it is.

Cheers

Vladimir

--
That woman speaks eight languages and can't say "no" in any of them.
-- Dorothy Parker

[copx]

"copx" <in*****@invalid.com> schrieb im Newsbeitrag
news:ds*************@news.t-online.com...

Is the "-" operator (meaning * (-1) ) part of the standard?

[snip]

Thank you for the answers!