what is fun1()->fun2(params)

[rushik]

Hello,

In our code i've seen somewhere fun1()->fun2(params), i m not able to
understand what it means? our code is completely written in C++.

Thanks
Ru.

[Victor Bazarov]

rushik wrote:

In our code i've seen somewhere fun1()->fun2(params), i m not able to
understand what it means? our code is completely written in C++.

fun1() is a function call that probably returns a pointer to an object
of some class that has a member named 'fun2'. Like that:

class Foo {
public:
void fun2(int);
};

Foo* fun1();

int main() {
int params = 42;
fun1()->fun2(params);
}

You can rewrite it with a named object in the middle:

...
Foo* ptr = fun1();
ptr->fun2(params);

Basically it's the same thing.

V

[Alf P. Steinbach]

* rushik:

In our code i've seen somewhere fun1()->fun2(params), i m not able to
understand what it means? our code is completely written in C++.

fun1 is a function returning a pointer to an object with a fun2 member
function.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?

[Shark]

and also an ugly variant

try { (*fun1()).fun2(params); }

variant + you're sure *ptr is not null.