471,585 Members | 1,165 Online

# Converting a character array to single hex value

So i have a tachometer that I can communicated with via UART which
gives me a character array of ascii values in the following form:

Standard ascii 7 characters including decimal point such that the array
when printed would equal the rpm value ie

2031.00 rpm = [ '2','0','3','1','.','0','0' ]

I've been rummaging everywhere and can't find anything to tackle this.
I would be extreemly greatful to anyone that can point me in the right
direction or that has any code snippets in C that I can use.

NN

Jan 9 '06 #1
12 8445
so the idea is if the array is

[ '2','0','3','1','.','0','0' ]

then the output of the conversion would be

07EF (I'm not interested in the decimal and it can be truncated)

Jan 9 '06 #2
ni*********@gmail.com wrote:
so the idea is if the array is

[ '2','0','3','1','.','0','0' ]

then the output of the conversion would be

07EF (I'm not interested in the decimal and it can be truncated)

If you can convert that to an integer, you can format it
as you like using printf/sprintf.

char foo[] = "2031.00";
char *tmp;
if((tmp = strchr(foo,'.')) != NULL) {
int val;
*tmp = 0;
val = atoi(foo); /*use strtol and do better error checking*/
printf("%X\n",val);
}

or perhaps

char foo[] = "2031.00";
int val = 0,i;
for(i = 0; foo[i] != 0 && foo[i] != '.'; i++) {
if(isdigit((unsigned int)foo[i]) {
val = val*10 + foo[i] - '0';
} else {
/*ouch, bail out */
}

}

printf("%X",val);
Jan 9 '06 #3
ni*********@gmail.com wrote:
so the idea is if the array is

[ '2','0','3','1','.','0','0' ]

then the output of the conversion would be

07EF (I'm not interested in the decimal and it can be truncated)

In addition, state enough information so that we know what
you want.
My guess is that you want to convert from an
array 7 of char to a string containing a hex number.

Make it two parts: Retrieving the number from the input
and outputting it as you want.

Getting the number:
You can do the whole thing character for character by
yourself.
Or, if you can guarantee that you always have a '.', then
you can use strtoul() to retrieve the number. However,
I'd rather make the input a string to be on the safe side.
Or, if you are sure about the number of characters, you
can use sscanf(input, "%7lu", &num) or similar.

Output:
snprintf(), if available, sprintf() otherwise. Have a look
at flags and fieldwidth in the documentation.

Cheers
Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.
Jan 9 '06 #4
Nils O. Selåsdal wrote:
ni*********@gmail.com wrote:
so the idea is if the array is

[ '2','0','3','1','.','0','0' ]

then the output of the conversion would be

07EF (I'm not interested in the decimal and it can be truncated)

If you can convert that to an integer, you can format it
as you like using printf/sprintf.

char foo[] = "2031.00";

<snip>

The OP's first post specifically wanted foo to be
char foo[7] = {'2','0','3','1','.','0','0'};

Cheers
Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.
Jan 9 '06 #5
Michael Mair wrote:
Nils O. Selåsdal wrote:
ni*********@gmail.com wrote:
so the idea is if the array is

[ '2','0','3','1','.','0','0' ]

then the output of the conversion would be

07EF (I'm not interested in the decimal and it can be truncated)

If you can convert that to an integer, you can format it
as you like using printf/sprintf.

char foo[] = "2031.00";

<snip>

The OP's first post specifically wanted foo to be
char foo[7] = {'2','0','3','1','.','0','0'};

I didn't see that requirement specifically set, and even if it was,
why not add an extra element to the not-overly-large array and add a nul
terminator after he read the characters from his uart for simplicity ?
Jan 9 '06 #6
ni*********@gmail.com wrote:
So i have a tachometer that I can communicated with via UART which
gives me a character array of ascii values in the following form:

Standard ascii 7 characters including decimal point such that the array
when printed would equal the rpm value ie

2031.00 rpm = [ '2','0','3','1','.','0','0' ]

I've been rummaging everywhere and can't find anything to tackle this.
I would be extreemly greatful to anyone that can point me in the right
direction or that has any code snippets in C that I can use.

Look up the strto functions, such as strtod or, alternatively, sscanf.
Don't forget to ensure the string is null terminated though, since all
the C string functions rely on null termination.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.
Jan 9 '06 #7
ni*********@gmail.com wrote:

So i have a tachometer that I can communicated with via UART
which gives me a character array of ascii values in the
following form:

Standard ascii 7 characters including decimal point such that
the array when printed would equal the rpm value ie

2031.00 rpm = [ '2','0','3','1','.','0','0' ]

I've been rummaging everywhere and can't find anything to tackle
this. I would be extreemly greatful to anyone that can point me
in the right direction or that has any code snippets in C that I
can use.

The "UART" is actually mapped into a text file. Open that and read
the appropriate data. You can either use the bulky and awkward
scanf routines, or use some routines I published here for text
input without buffering. Google search here (and possibly on
comp.arch.embedded) for posts from me with the phrase "txtinput.c".

--
"If you want to post a followup via groups.google.com, don't use
the broken "Reply" link at the bottom of the article. Click on
"show options" at the top of the article, then click on the
Jan 10 '06 #8
Thanks everyone. Great suggestions.

However. I'm trying to avoid using any string functions being that the
bulk of my code in other areas won't need it. The UART will be giving
be an 8-bit value as each ascii character comes in. So I'm puting those
values into a 7 element char array. That array is guarenteed to have a
decimal though the index position of that decimal is not guarenteed, it
is also guarenteed to have 7 elements. Once the array is full it will
have a value such as

[ '2','0','3','1','.','0','0' ]

which then needs to be translated to 2, 8bit values

[07 , EF] or similarly, a 2 element char array.

Sorry if my OP was unclear.

Jan 10 '06 #9
Actually, its mapped to a register in the processor. I'm extracting
each byte as it comes in and copying it to the array at each interrupt
generated by the processor, so I don't think i can use those stream
manipulation routines.

Jan 10 '06 #10
nikNjegovan wrote:
Thanks everyone. Great suggestions.

However. I'm trying to avoid using any string functions being that the
bulk of my code in other areas won't need it. The UART will be giving
be an 8-bit value as each ascii character comes in. So I'm puting those
values into a 7 element char array. That array is guarenteed to have a
decimal though the index position of that decimal is not guarenteed, it
is also guarenteed to have 7 elements. Once the array is full it will
have a value such as

[ '2','0','3','1','.','0','0' ]

which then needs to be translated to 2, 8bit values

[07 , EF] or similarly, a 2 element char array.

Sorry if my OP was unclear.

In that case, rolling your own might be simplest. Given that the C
standard (and probably the character set specified for your serial
interface) guarantee that the digits are in order, a simple loop
multiplying by 10 and adding (character - '0') should do you. You might
find the isdigit function of use as well.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.
Jan 10 '06 #11
nikNjegovan wrote:
Actually, its mapped to a register in the processor.
What is? Please provide context when posting, people might not have seen
I'm extracting
each byte as it comes in and copying it to the array at each interrupt
generated by the processor, so I don't think i can use those stream
manipulation routines.

That does make using stream routines hard, but there are string
equivalents of some of them, such as sscanf.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.
Jan 11 '06 #12
nikNjegovan wrote:
Thanks everyone. Great suggestions.

However. I'm trying to avoid using any string functions being that the
bulk of my code in other areas won't need it. The UART will be giving
be an 8-bit value as each ascii character comes in. So I'm puting those
values into a 7 element char array. That array is guarenteed to have a
decimal though the index position of that decimal is not guarenteed, it
is also guarenteed to have 7 elements. Once the array is full it will
have a value such as

[ '2','0','3','1','.','0','0' ]

which then needs to be translated to 2, 8bit values

[07 , EF] or similarly, a 2 element char array.

Sorry if my OP was unclear.

Use C notation if you're talking about C arrays.

If you have a

char c[7] = {'2','0','3','1','.','0,'0'};

And what to convert this according to what you say above, the boring
way, first do proper validation so you know you got all digits, and
only digits, then;

unsigned char val[2];
int i = (c[0] - '0') *1000 + (c[1]*100 - '0') +
(c[2]*10 -'0' + (c[3] - '0');

val[0] = (i&0xff00) >> 8;
val[1] = i&0xff;

Or did you want the ascii hex representation of them ?
Jan 11 '06 #13

### This discussion thread is closed

Replies have been disabled for this discussion.