Why such output?

[SinC]

Here is the program code:

typedef void (*T)(void);

void id(void)
{
int z;
(*(((T *)(&z))+ 2))();
cout<<"y";
}
void Magic(void)
{
cout<<"magic\n";
id();
cout<<"x\n";
}
int main(void)
{
Magic();
cout<<"a\n";
return 0;
}

The output of this program is (g++ compiler) :
magic
x
x
a

Can somebody tell me, what is going on here in this whole code?
Thanks.

[pemo]

"SinC" <ch*********@gmail.com> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

Here is the program code:

typedef void (*T)(void);

void id(void)
{
int z;
(*(((T *)(&z)) + 2))();
cout<<"y";
}
void Magic(void)
{
cout<<"magic\n";
id();
cout<<"x\n";
}
int main(void)
{
Magic();
cout<<"a\n";
return 0;
}

The output of this program is (g++ compiler) :
magic
x
x
a

Can somebody tell me, what is going on here in this whole code?

Firstly, this is C++, and c.l.c is a group dedicated to C. So, you should
ask your question on, say, comp.lang.c++.

Secondly, the code is, um, rather suspect!

The bit I assume you're interested in is?
int z;
(*(((T *)(&z))+ 2))();

This appears to be taking the address of an unitialised int (address of
frame variable!), casting that to be a function pointer, adding 2 to it,
calling the function pointed to!!!!

I doubt whether this is portable!!!!!

[Dick de Boer]

"SinC" <ch*********@gmail.com> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

Here is the program code:

Can somebody tell me, what is going on here in this whole code?
Thanks.

z in function ID is allocated on stack. The return adres pushed when calling
id() is also on stack. It seems that &z + 2 adrresses the reurun adres of
the calling function. Here, character x is written. After that the result
depends strongly on implementation of the stackframe.

I hope for you this isn't a serious program....
DickB

[Keith Thompson]

"Dick de Boer" <ddeboer - dsp.com> writes:

"SinC" <ch*********@gmail.com> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

Here is the program code:

Can somebody tell me, what is going on here in this whole code?
Thanks.

z in function ID is allocated on stack. The return adres pushed when calling
id() is also on stack. It seems that &z + 2 adrresses the reurun adres of
the calling function. Here, character x is written. After that the result
depends strongly on implementation of the stackframe.

It depends strongly on the implementation long before that. There's
no guarantee that there's such a thing as a "stack" or a "stackframe",
or that the return address (if any) is stored somewhere in it.

--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.

[Mike Wahler]

"SinC" <ch*********@gmail.com> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

Here is the program code:

typedef void (*T)(void);

void id(void)
{
int z;
(*(((T *)(&z))+ 2))();
cout<<"y";
}
void Magic(void)
{
cout<<"magic\n";
id();
cout<<"x\n";
}
int main(void)
{
Magic();
cout<<"a\n";
return 0;
}

The output of this program is (g++ compiler) :
magic
x
x
a

Can somebody tell me, what is going on here in this whole code?

What output did you expect and why?

-Mike