template argument to a template class

[anujanujdhamija]

I am unable to figure out how to instantiate class temp below.
"temp<int, b<int, int> >" causes error:
error: type/value mismatch at argument 2 in template parameter
list for `template<class T, template<int <anonymous>, int
<anonymous> >
class T2> class temp'

/************************************************** ********************************************/
#include<iostream>
using namespace std;

template<class T, template<int, int>class T2>
class temp
{
T val;
public:
void print()
{
cout<<val;
}
};

class a
{
};

template<class T1, class T2>
class b
{
};

template<class
void method(temp<int, b<int, int> > li,temp<a, b<int,int> > la)
{
li.print();
}

int main()
{

temp<int, b<int, int> > ti;
temp<a, b<int, int> > ta;

method(ti, ta);

return 0;
}
/************************************************** ********************************************/

[anujanujdhamija]

please ignore incomplete statement "template<class" just before
definition of method(). It was a copy-paste error.

[Rob Williscroft]

wrote in news:11**********************@g44g2000cwa.googlegr oups.com in
comp.lang.c++:

I am unable to figure out how to instantiate class temp below.
"temp<int, b<int, int> >" causes error:
error: type/value mismatch at argument 2 in template parameter
list for `template<class T, template<int <anonymous>, int
<anonymous> >
class T2> class temp'

/************************************************** ********************
************************/ #include<iostream>
using namespace std;

template<class T, template<int, int>class T2>
class temp
{
T val;
public:
void print()
{
cout<<val;
}
};

class a
{
};

template<class T1, class T2>
class b
{
};

You need 'b' to have 'int' arguments not 'class', something like:

template <int A, int B >
class b
{
};
template<class
void method(temp<int, b<int, int> > li,temp<a, b<int,int> > la)
{
li.print();
}

int main()
{

temp<int, b<int, int> > ti;
Would become:
temp< int, b<1, 2> > t_int_1_2;
temp<a, b<int, int> > ta;

method(ti, ta);

return 0;
}

Alternitively change you defenition of 'temp':

template < typename T, template < typename T1, typename T2 > class C >
class temp
{
};

Now 'temp' will work with your original defenition of 'b':

temp< int, b< int, int > > ti;

Depends what you wan't to do.

Rob.
--
http://www.victim-prime.dsl.pipex.com/