about consts and function overloading

[nick]

ex1.foo(Person p);
foo(const Person p);

ex2.foo(Person *p);
foo(const Person *p);

ex3.foo(Person p);
foo(Person p) const;

why the pairs in ex1 are treated as the same function.Invalid
overloading. but ex2 is ok?

what is the meaning is ex3(foo(Person p)const;)?

thanks!

[Ivan Vecerina]

Nick,
I'm afraid this batch of questions looks too much like homework or
something like that...
Searching the FAQs would provide you the answers.

"nick" <i1********@yahoo.com> wrote in message
news:dl***********@justice.itsc.cuhk.edu.hk...
: ex1.
: foo(Person p);
: foo(const Person p);

When a parameter is passed by value, the 'const' applies to the copy
of the object used within function foo.
Overloading will work as expected if you pass the parameter by
reference:
void foo( Person& p );
void foo( Person const& p );

: ex2.foo(Person *p);
: foo(const Person *p);
Note that the implementation of the first function could be written
as:
void foo( Person * const p ) { /* ... code ... */ };

: ex3.foo(Person p);
: foo(Person p) const;
:
: why the pairs in ex1 are treated as the same function.Invalid
: overloading. but ex2 is ok?
:
: what is the meaning is ex3(foo(Person p)const;)?
I'll leave this answer up to you.

Ivan
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