manipulate string

[crovax75]

LS,

I've a problem to get the year, month and day from the following
string: "20051027"

--

#include <stdio.h>
#include <string.h>

char str[9]="20051027";

char year[5], month[3], day[3];


int main(void){

printf("String str: %s\n",str);
strncpy(year, str, 4);
year[4] = '\0';
printf("%s\n", year);
//But how to get the month in the string 'str'?
printf("Year:%s\n",year);
printf("Month:%s\n",month);
printf("Day:%s\n",day);

getchar();
return 0;
}

--

PS. It is not a problem to concert it to integers.

Greetz,

Marcel

[Christopher Benson-Manica]

cr******@hotmail.com wrote:

#include <stdio.h>
#include <string.h> char str[9]="20051027"; char year[5], month[3], day[3]; int main(void){ strncpy(year, str, 4);
If you're feeling adventurous, you could use sscanf() for this task.
The following is easier, though...

sprintf( year, "%.4s", str );
sprintf( month, "%.2s", str+4 );
sprintf( day, "%.2s", str+6 );

assuming, of course, that you have somehow verified that str is in the
format you expect.
year[4] = '\0';
printf("%s\n", year);

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[Jirka Klaue]

Christopher Benson-Manica:

cr******@hotmail.com:

char str[9]="20051027";

.... If you're feeling adventurous, you could use sscanf() for this task.
IMO sscanf is *the* tool for this task.

unsigned y, m, d; /* if you insist on strings, do the obvious */

if (3 == sscanf(str, "%4u%2u%2u", &y, &m, &d))
printf("%u %u %u\n", y, m, d);
The following is easier, though...

sprintf( year, "%.4s", str );
sprintf( month, "%.2s", str+4 );
sprintf( day, "%.2s", str+6 );
Well, longer. More error-prone. But easier?
assuming, of course, that you have somehow verified that str is in the
format you expect.

OK, sscanf can do this for you.

Jirka

[Gow]

Christopher Benson-Manica wrote:

cr******@hotmail.com wrote:

#include <stdio.h>
#include <string.h>

char str[9]="20051027";

char year[5], month[3], day[3];

int main(void){

strncpy(year, str, 4);

If you're feeling adventurous, you could use sscanf() for this task.
The following is easier, though...

sprintf( year, "%.4s", str );
sprintf( month, "%.2s", str+4 );
sprintf( day, "%.2s", str+6 );

assuming, of course, that you have somehow verified that str is in the
format you expect.

year[4] = '\0';
printf("%s\n", year);

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

Or if you want to have the same approach you can do it as below.

#include <stdio.h>
#include <string.h>

char str[9]="20051027";

char year[5], month[3], day[3];

int main(void){

printf("String str: %s\n",str);

strncpy(year, str, 4);
year[4] = '\0';
printf("%s\n", year);

strncpy(month,&str[4],2);
month[3]='\0';
printf("%s\n", month);

strncpy(day,&str[6],2);
day[3]='\0';
printf("%s\n", day);

}

[Christopher Benson-Manica]

Jirka Klaue <jk****@tkn.tu-berlin.de> wrote:

Well, longer. More error-prone. But easier?

It's less tricky to do correctly than *scanf(), at least as has been
shown by some recent posts.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[crovax75]

Christopher Benson-Manica wrote:

Jirka Klaue <jk****@tkn.tu-berlin.de> wrote:

Well, longer. More error-prone. But easier?

It's less tricky to do correctly than *scanf(), at least as has been
shown by some recent posts.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

Hi all,

It works well with:

sprintf( year, "%.4s", str );
sprintf( month, "%.2s", str+4 );
sprintf( day, "%.2s", str+6 );

I want to thanks all of you for the fast replies!

Marcel

[Dave Thompson]

On 27 Oct 2005 08:35:46 -0700, "Gow" <go*****@gmail.com> wrote:
<snip>

char str[9]="20051027";

char year[5], month[3], day[3];

int main(void){

printf("String str: %s\n",str);

strncpy(year, str, 4);
year[4] = '\0';
printf("%s\n", year);

strncpy(month,&str[4],2);
month[3]='\0';
printf("%s\n", month);

strncpy(day,&str[6],2);
day[3]='\0';
printf("%s\n", day);
Nit: month[2] and day[2].
}

- David.Thompson1 at worldnet.att.net