why it is not giving any error?

[prasi]

hi all,
I have executed the following program, I was expecting some errors in
the program but it didn't give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
#include<stdio.h>
int main()
{
char a=97;

"hello everyone"+printf("value of a=%c\n",a);
return 0;
}

Thanks in advance
Prasanna K P

[August Karlstrom]

prasi wrote:

hi all,
I have executed the following program, I was expecting some errors in
the program but it didn't give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
#include<stdio.h>
int main()
{
char a=97;

"hello everyone"+printf("value of a=%c\n",a);
return 0;
}

Adding an integer to a character pointer is a well defined operation (It
has no side effect in your example though.) For instance:

char *s = "xyz";

printf("%c\n", *(s + 2));

will output 'z'.
August

[David G. Hong]

> #include<stdio.h>

int main()
{
char a=97;

You have assigned a decimal value of 97 to char variable 'a'. This
infact is legal in C as characters use ascii conversion. Not too sure
about why, but if you type in google, "ascii code" you will see
decimals numbers assigned to each character.

[Chris Dollin]

prasi wrote:

hi all,
I have executed the following program, I was expecting some errors in
the program but it didn't give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
#include<stdio.h>
int main()
{
char a=97;

"hello everyone"+printf("value of a=%c\n",a);
return 0;
}

There's nothing wrong with the code.

It's /stupid/, but there's no obligation on a compiler to detect
stupid code.

97 is legal as a character value (ill-advised, but legal).

Adding integers to pointers is legal - C would be pretty useless if
it were not - and ignoring calculated values is also legal and
often useful.

You might get some messages if you poked your compiler options a
bit harder.

--
Chris "electric hedgehog" Dollin
"I know three kinds: hot, cool, and what-time-does-the-tune-start?"

[Lew Pitcher]

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David G. Hong wrote:

#include<stdio.h>
int main()
{
char a=97;

You have assigned a decimal value of 97 to char variable 'a'. This
infact is legal in C

True so far.
as characters use ascii conversion.

Untrue.

The C standard -does not_ specify which characterset is used, and standard C has
been implemented in other charactersets other than ASCII.

On the platforms that I use,

char a=97;

assigns the variable a the value associated with the SOLIDUS ('/') character.
Needless to say, the characterset is _not_ ASCII.

[snip]
- --
Lew Pitcher
IT Specialist, Enterprise Data Systems,
Enterprise Technology Solutions, TD Bank Financial Group

(Opinions expressed are my own, not my employers')
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[pete]

Lew Pitcher wrote:

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David G. Hong wrote:

#include<stdio.h>
int main()
{
char a=97;

You have assigned a decimal value of 97 to char variable 'a'. This
infact is legal in C

True so far.

as characters use ascii conversion.

Untrue.

It's legal because CHAR_MAX is guaranteed to be at least 127,
and CHAR_MIN is guaranteed to be no greater than zero.

--
pete

[Lew Pitcher]

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pete wrote:

Lew Pitcher wrote:

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Hash: SHA1

David G. Hong wrote:

#include<stdio.h>
int main()
{
char a=97;
You have assigned a decimal value of 97 to char variable 'a'. This
infact is legal in C

True so far.

as characters use ascii conversion.

Untrue.

It's legal because CHAR_MAX is guaranteed to be at least 127,
and CHAR_MIN is guaranteed to be no greater than zero.

Which is entirely irrelevant to this thread.

The issue is whether or not "characters use ascii conversion" is a valid
statement, not whether 97 is a value between CHAR_MIN and CHAR_MAX.

- --
Lew Pitcher
IT Specialist, Enterprise Data Systems,
Enterprise Technology Solutions, TD Bank Financial Group

(Opinions expressed are my own, not my employers')
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[pete]

Lew Pitcher wrote:

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pete wrote:

Lew Pitcher wrote:

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David G. Hong wrote:

>#include<stdio.h>
>int main()
>{
>char a=97;
You have assigned a decimal value of 97 to char variable 'a'. This
infact is legal in C

True so far.
as characters use ascii conversion.

Untrue.

It's legal because CHAR_MAX is guaranteed to be at least 127,
and CHAR_MIN is guaranteed to be no greater than zero.

Which is entirely irrelevant to this thread.

No. The subject line is:
why it is not giving any error?

The reason why
char a=97;
is not giving any error, was attempted by David G. Hong.

I gave the correct reason.

ASCII is irrelevant to OP's question.

--
pete

[Martin Ambuhl]

prasi wrote:

hi all,
I have executed the following program, I was expecting some errors in
the program but it didn't give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
No one can explain you. Let's get back to your code. What errors were
you expecting? Why? You would learn more from examining your false
expectations. Asking us to explain all the errors *not* in this code is
silly: that list would be inexhaustible.

And what makes you think wanton repetition of exclamation marks
accomplishes anything?
#include<stdio.h>
int main()
{
char a=97;

"hello everyone"+printf("value of a=%c\n",a);
return 0;
}

Thanks in advance
Prasanna K P

[Martin Ambuhl]

David G. Hong wrote:

#include<stdio.h>
int main()
{
char a=97;

You have assigned a decimal value of 97 to char variable 'a'. This
infact is legal in C as characters use ascii conversion.

It is legal to assign to a char any value in the range CHAR_MIN to
CHAR_MAX. This has nothing to do with the character sets used.
There is nothing that specifies that C use ASCII (note caps). The word
'conversion' is a bit off the mark as well.

[Christopher Benson-Manica]

Martin Ambuhl <ma*****@earthlink.net> wrote:

It is legal to assign to a char any value in the range CHAR_MIN to
CHAR_MAX.

Does it matter whether the char in question is signed or unsigned?

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[Flash Gordon]

Christopher Benson-Manica wrote:

Martin Ambuhl <ma*****@earthlink.net> wrote:

It is legal to assign to a char any value in the range CHAR_MIN to
CHAR_MAX.

Does it matter whether the char in question is signed or unsigned?

Not for the truth of Martin's statement, nor for the assignment of 97.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.

[Martin Ambuhl]

Christopher Benson-Manica wrote:

Martin Ambuhl <ma*****@earthlink.net> wrote:

It is legal to assign to a char any value in the range CHAR_MIN to
CHAR_MAX.

Does it matter whether the char in question is signed or unsigned?

a char is in the range CHAR_MIN to CHAR_MAX,
a signed char is in the range SCHAR_MIN (-127 or less) to SCHAR_MAX
(+127 or more)
an unsigned char is in the range 0 to UCHAR_MAX (+255 or more)

The OP's code used 97, which is always in range for a char, signed char,
or unsigned char. He initialized a char with this value, so only
CHAR_MIN and CHAR_MAX are relevant.