LOCAL(int *) function_name (int a, char *b) { code... }
I wanted to know what the LOCAL keyword indicates in this declaration?
Nothing whatsoever, as far as C is concerned. In fact, in straight C
this is a syntax error. Since it's capitalised, it's probably #defined
as a macro somewhere else in your code, with a definition that both
makes this syntactical and explains its meaning.
Hello there,
after some time of pondering I come to some solution which would suit
me best. Please correct, if I am wrong.
Function has two parameters. A string array, better said a pointer to...
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