424,853 Members | 1,563 Online
+ Ask a Question
Need help? Post your question and get tips & solutions from a community of 424,853 IT Pros & Developers. It's quick & easy.

# Integer and character manipulation

 P: n/a Hello, I need some help with the following: 1) I need to split a 16bit INT into two 8bit characters, and then be able to join these two characters to form again the original 16bit integer. For example with values expressed in binary: int n= 000000001111111; --> char a=00000000; --> char b=11111111; and then be able to join a and b to form back n. 2) And last, I need to convert an integer into a string. For example, int n=3.142 ---> char string[5] = ['3','.','1','4','2'] Thank you very much!! I've tried working with casting but as far as I know they don't seem to be the answer. I've also searched numerous tutorials and web pages, but nothing productive. Any help or suggestion will be highly appreciated. Thank you very much!! Nov 15 '05 #1
10 Replies

 P: n/a ru****@gmail.com wrote: Hello, I need some help with the following: 1) I need to split a 16bit INT into two 8bit characters, and then be able to join these two characters to form again the original 16bit integer. For example with values expressed in binary: int n= 000000001111111; --> char a=00000000; --> char b=11111111; and then be able to join a and b to form back n. You can use a mask for that. a = n & 0xff00; b = n & 0x00ff; And use 'unsigned char' instead of 'char'. 'char' can be either equivalent to 'unsigned char' or 'signed char'. If you rely on signed char and use some value that cannot be represented with signed char, then you may invoke implementation defined behavior or raise an implementation defined signal. 2) And last, I need to convert an integer into a string. For example, int n=3.142 ---> char string[5] = ['3','.','1','4','2'] 'int' is a part of the standard integer types and can't be used to represent rationals. So you should either use an object type of float or double. To produce a string from a given value of type float or double, use sprintf/snprintf Thank you very much!! I've tried working with casting but as far as I know they don't seem to be the answer. I've also searched numerous tutorials and web pages, but nothing productive. Any help or suggestion will be highly appreciated. Thank you very much!! casting is not a magical thing. The reason casting exists in the language is for a few corner cases, namely: %p expecting a (void *) with *printf family of functions. To compare the return value of mktime to (time_t)-1 in case of error. For the is*, to* functions/macros. There may be one or two other places that escape me at the moment but not much else beyond that. The reason it doesn't produce a string is because a cast yields a value of a given type, given a value. As there does not exist a string type in C, then you can't expect that there will be a string produced by a cast. -- aegis Nov 15 '05 #2

 P: n/a On 5 Sep 2005 12:03:12 -0700, ru****@gmail.com wrote: Hello, I need some help with the following:1) I need to split a 16bit INT into two 8bit characters, and then beable to join these two characters to form again the original 16bitinteger.For example with values expressed in binary:int n= 000000001111111;--> char a=00000000;--> char b=11111111;and then be able to join a and b to form back n. Look at the bitwise operators, especially "and" and shift. 2) And last, I need to convert an integer into a string.For example,int n=3.142 ---> char string[5] = ['3','.','1','4','2'] 3.142 is not an integer value of any kind. Your array is not a string. Perhaps you'd like to tell us what you really need rather than provide an incorrect example. Thank you very much!! I've tried working with casting but as far as Iknow they don't seem to be the answer. I've also searched numeroustutorials and web pages, but nothing productive. Any help orsuggestion will be highly appreciated. Thank you very much!! You will get a lot more help if you post your code. We won't do you homework for you. <> Nov 15 '05 #3

 P: n/a On 5 Sep 2005 13:49:26 -0700, "aegis" wrote: ru****@gmail.com wrote: Hello, I need some help with the following: 1) I need to split a 16bit INT into two 8bit characters, and then be able to join these two characters to form again the original 16bit integer. For example with values expressed in binary: int n= 000000001111111; --> char a=00000000; --> char b=11111111; and then be able to join a and b to form back n.You can use a mask for that.a = n & 0xff00; You are missing a shift. On most systems, the result of your expression will not fit in a char. b = n & 0x00ff;And use 'unsigned char' instead of 'char'. 'char' can be eitherequivalent to 'unsigned char' or 'signed char'. If you rely on signedchar and use some value that cannot be represented with signed char,then you may invoke implementation defined behavior or raise animplementation defined signal. 2) And last, I need to convert an integer into a string. For example, int n=3.142 ---> char string[5] = ['3','.','1','4','2']'int' is a part of the standard integer types and can't be used torepresent rationals. So you should either use an object type of floator double. To produce a string from a given value of type float ordouble, use sprintf/snprintf Thank you very much!! I've tried working with casting but as far as I know they don't seem to be the answer. I've also searched numerous tutorials and web pages, but nothing productive. Any help or suggestion will be highly appreciated. Thank you very much!!casting is not a magical thing. The reason casting exists in thelanguage is for a few corner cases, namely: %p expecting a (void *)with *printf family of functions. To compare the return value of mktimeto (time_t)-1 in case of error. For the is*, to* functions/macros.There may be one or two other places that escape me at the moment butnot much else beyond that. The reason it doesn't produce a string isbecause a cast yields a value of a given type, given a value. As theredoes not exist a string type in C, then you can't expect that therewill be a string produced by a cast. <> Nov 15 '05 #4

 P: n/a ru****@gmail.com wrote: Hello, I need some help with the following: 1) I need to split a 16bit INT into two 8bit characters, and then be able to join these two characters to form again the original 16bit integer. For example with values expressed in binary: int n= 000000001111111; --> char a=00000000; --> char b=11111111; and then be able to join a and b to form back n. Sounds like homework! Mug up on shifting and masking. 2) And last, I need to convert an integer into a string. For example, int n=3.142 ---> char string[5] = ['3','.','1','4','2'] 3.142.isn't an int, its a floating point value. Look up formatted output. Ian Nov 15 '05 #5

 P: n/a Barry Schwarz wrote: On 5 Sep 2005 13:49:26 -0700, "aegis" wrote:ru****@gmail.com wrote: Hello, I need some help with the following: 1) I need to split a 16bit INT into two 8bit characters, and then be able to join these two characters to form again the original 16bit integer. For example with values expressed in binary: int n= 000000001111111; --> char a=00000000; --> char b=11111111; and then be able to join a and b to form back n.You can use a mask for that.a = n & 0xff00; You are missing a shift. On most systems, the result of your expression will not fit in a char. Oops. Indeed. That should have been a = (n & 0xff00) >> 8; b = n & 0x00ff;And use 'unsigned char' instead of 'char'. 'char' can be eitherequivalent to 'unsigned char' or 'signed char'. If you rely on signedchar and use some value that cannot be represented with signed char,then you may invoke implementation defined behavior or raise animplementation defined signal. 2) And last, I need to convert an integer into a string. For example, int n=3.142 ---> char string[5] = ['3','.','1','4','2']'int' is a part of the standard integer types and can't be used torepresent rationals. So you should either use an object type of floator double. To produce a string from a given value of type float ordouble, use sprintf/snprintf Thank you very much!! I've tried working with casting but as far as I know they don't seem to be the answer. I've also searched numerous tutorials and web pages, but nothing productive. Any help or suggestion will be highly appreciated. Thank you very much!!casting is not a magical thing. The reason casting exists in thelanguage is for a few corner cases, namely: %p expecting a (void *)with *printf family of functions. To compare the return value of mktimeto (time_t)-1 in case of error. For the is*, to* functions/macros.There may be one or two other places that escape me at the moment butnot much else beyond that. The reason it doesn't produce a string isbecause a cast yields a value of a given type, given a value. As theredoes not exist a string type in C, then you can't expect that therewill be a string produced by a cast. <> Nov 15 '05 #6

 P: n/a Hi to all, Firstly thank you very much all of you for such a quick answer. Using the bitwise operators was the important hint, and yes, after using the masks and shifting 8 positions I've finally got the high byte and low byte separated as two 8 bit characters as I needed. As for the second part, sorry, of course 3.142 isn't an int, just quick writing and bad example. I'havent tried that part yet, but after more searching I think that fcvtf will probably do the job. Posting the whole code wont probably help, as these are just two little parts I need for doing the big task. It is not actually homework, but something I need to do after some long time without coding (and wasn't too good either when I used to code more often). Thank you once again :) I'll let you know If I encounter problems with the second part, though I hope I don't ;) Ian wrote: ru****@gmail.com wrote: Hello, I need some help with the following: 1) I need to split a 16bit INT into two 8bit characters, and then be able to join these two characters to form again the original 16bit integer. For example with values expressed in binary: int n= 000000001111111; --> char a=00000000; --> char b=11111111; and then be able to join a and b to form back n. Sounds like homework! Mug up on shifting and masking. 2) And last, I need to convert an integer into a string. For example, int n=3.142 ---> char string[5] = ['3','.','1','4','2'] 3.142.isn't an int, its a floating point value. Look up formatted output. Ian Nov 15 '05 #7

 P: n/a On 5 Sep 2005 14:38:26 -0700, ru****@gmail.com wrote: Hi to all, Firstly thank you very much all of you for such a quick answer.Using the bitwise operators was the important hint, and yes, afterusing the masks and shifting 8 positions I've finally got the high byteand low byte separated as two 8 bit characters as I needed.As for the second part, sorry, of course 3.142 isn't an int, just quickwriting and bad example. I'havent tried that part yet, but after moresearching I think that fcvtf will probably do the job. Is fcvtf a standard function? <> Nov 15 '05 #8

 P: n/a On Mon, 05 Sep 2005 14:30:25 -0700, aegis wrote: Barry Schwarz wrote: On 5 Sep 2005 13:49:26 -0700, "aegis" wrote: .... >You can use a mask for that. > >a = n & 0xff00; You are missing a shift. On most systems, the result of your expression will not fit in a char. Oops. Indeed. That should have been a = (n & 0xff00) >> 8; That can have problems on systems with 16 bit ints because you could be shifting a negative value. Lawrence Nov 15 '05 #9

 P: n/a Lawrence Kirby writes: On Mon, 05 Sep 2005 14:30:25 -0700, aegis wrote: Barry Schwarz wrote: On 5 Sep 2005 13:49:26 -0700, "aegis" wrote: ...You can use a mask for that. > >a = n & 0xff00; You are missing a shift. On most systems, the result of your expression will not fit in a char. Oops. Indeed. That should have been a = (n & 0xff00) >> 8; That can have problems on systems with 16 bit ints because you could be shifting a negative value. If ints were 16 bits, I'd be inclined to think 0xff00 would be an unsigned int, which means n would be converted to unsigned int before the '&' were done; the shift would then be working on an unsigned int. Nov 15 '05 #10

 P: n/a On Tue, 06 Sep 2005 03:14:13 -0700, Tim Rentsch wrote: .... If ints were 16 bits, I'd be inclined to think 0xff00 would be an unsigned int, which means n would be converted to unsigned int before the '&' were done; the shift would then be working on an unsigned int. You're right, the problem in this case isn't in shifting a negative value, is is converting a negative value to an unsigned type which won't preserve the bit pattern on 1's complement and sign-magnitude based implementations. Lawrence Nov 15 '05 #11

### This discussion thread is closed

Replies have been disabled for this discussion.