how will u call this fn

[recklinux]

ok guys
its
void *fn(int *a,int *b);
main
{
-----
-----
}
how will you call this fn without using it in main ?

[Michael Mair]

re*******@gmail.com wrote:

ok guys
its
void *fn(int *a,int *b);
main
{
-----
-----
}
how will you call this fn without using it in main ?

Try to rephrase your question in clear English; mention what you
want to achieve. Do not use pseudocode but a minimal example
exhibiting your problem. This helps us help you.

-Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.

[MCheu]

On 22 Aug 2005 12:34:51 -0700, re*******@gmail.com wrote:

ok guys
its
void *fn(int *a,int *b);
main
{
-----
-----
}
how will you call this fn without using it in main ?

I suppose an obvious solution would be to wrap fn() inside another
function and call that second function in main() instead of fn(). Of
course, depending on the cirumstances (which you haven't shared), this
may or may not be useful to you.
---------------------------------------------
Thanks.
MCheu

[Walter Roberson]

In article <11*********************@o13g2000cwo.googlegroups. com>,
<re*******@gmail.com> wrote:

ok guys
its
void *fn(int *a,int *b);
main
{
-----
-----
}
how will you call this fn without using it in main ?

Depends what you mean by "using" it. For example if you register
it as a signal handler or an atexit handler, then it will be invoked
and yet it will not be invoked "in main".

For some meanings of "using it": you could pass a pointer to the
function into a lower level routine and have it called there through
a function pointer. The function -pointer- will have been "mentioned"
in main, but not "used" in main [in the traditional "use" vs
"mention" sense.]

Also, your specific implementation may allow the entry point to
be changed to something other than main()

--
"This was a Golden Age, a time of high adventure, rich living and
hard dying... but nobody thought so." -- Alfred Bester, TSMD