Help needed in solving this problem

[sasiraj]

#include<stdio.h>

#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};

int main()
{
int d;

for(d=-1;d <= (TOTAL_ELEMENTS-2);d++)
printf("%d\n",array[d+1]);

return 0;
}

The above snippet doesnt print the array as expected.
I think the error is in the Test-condition in for loop.
If i cast it to INT [(int)TOTAL_ELEMENTS-2)] than its working fine.
y is it so..can sbd tell me what the return type of sizeof
is??

[Walter Roberson]

In article <11**********************@g44g2000cwa.googlegroups .com>,
sasiraj <va*********@gmail.com> wrote:

#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0])) int d; for(d=-1;d <= (TOTAL_ELEMENTS-2);d++) I think the error is in the Test-condition in for loop.
If i cast it to INT [(int)TOTAL_ELEMENTS-2)] than its working fine.
y is it so..can sbd tell me what the return type of sizeof
is??

sizeof has type size_t . The exact width of size_t is unspecified,
but one thing that -is- specified about it is that it is unsigned.
You might be having difficulty with comparing a negative int
to an unsigned integral type.
--
"This was a Golden Age, a time of high adventure, rich living and
hard dying... but nobody thought so." -- Alfred Bester, TSMD

[Rouben Rostamian]

In article <11**********************@g44g2000cwa.googlegroups .com>,
sasiraj <va*********@gmail.com> wrote:

#include<stdio.h>

#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};

int main()
{
int d;

for(d=-1;d <= (TOTAL_ELEMENTS-2);d++)
printf("%d\n",array[d+1]);

return 0;
}

The above snippet doesnt print the array as expected.
I think the error is in the Test-condition in for loop.
If i cast it to INT [(int)TOTAL_ELEMENTS-2)] than its working fine.
y is it so..can sbd tell me what the return type of sizeof
is??

From K&R2, Section A6.5:

[automatic conversion of operands]
If either operand is unsigned int, the other is
converted to unsigned int.

Thus the -1 in d=-1 is converted (unsigned int)(-1) which
generally is a pretty large number.

--
Rouben Rostamian

[ice]

sasiraj wrote:

#include<stdio.h>

#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};

int main()
{
int d;

for(d=-1;d <= (TOTAL_ELEMENTS-2);d++)
printf("%d\n",array[d+1]);

return 0;
}

The above snippet doesnt print the array as expected. hello sasi
Do you want to print the array in order as it is declared?If yes they
are printing in order .
and if no then clarify in which order? I think the error is in the Test-condition in for loop.
If i cast it to INT [(int)TOTAL_ELEMENTS-2)] than its working fine.
y is it so..can sbd tell me what the return type of sizeof
is??

[Jaspreet]

sasiraj wrote:

#include<stdio.h>

#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0])) Just make it:
#define TOTAL_ELEMENTS (signed)(sizeof(array) / sizeof(array[0]))

Try going through sizeof help and you would have the answer yourself.
int array[] = {23,34,12,17,204,99,16};

int main()
{
int d;

for(d=-1;d <= (TOTAL_ELEMENTS-2);d++) OR another choice could be to initialise d to 0. But I guess you did
not want this. Soo, go through sizeof help.
printf("%d\n",array[d+1]);

return 0;
}

The above snippet doesnt print the array as expected.
I think the error is in the Test-condition in for loop.
If i cast it to INT [(int)TOTAL_ELEMENTS-2)] than its working fine.
y is it so..can sbd tell me what the return type of sizeof
is??

[Jaspreet]

ice wrote:

sasiraj wrote:

[snip program]

The above snippet doesnt print the array as expected.

hello sasi
Do you want to print the array in order as it is declared?If yes they
are printing in order .
and if no then clarify in which order?

I think the error is in the Test-condition in for loop.
If i cast it to INT [(int)TOTAL_ELEMENTS-2)] than its working fine.
y is it so..can sbd tell me what the return type of sizeof
is??

I dont think its should print the contents without you modifying the
#define preprocessor. Please check once again.

OR probably I need to check my compiler. ;)