Returning pointer to array problem

[Carramba]

hi!

Iam trying to make program were I enter string and serach char.
and funktion prints out witch position char is found this
is done if funktion serach_char. so far all good
what I want do next is:
return, from funktion, pointer value to array were
positions ( of found char) is stored. and print that array from main.
but I only manage to print memory adress to array..

any suggestions?

so far everything works fine.

int search_char( char *pStr , char *pSearch );

int main(void){
char cStr[201];
char cSearch[21];
int *pInt;
int i ;
printf("Enter string\n",lillae);
scanf("%s", cStr);
printf("Enter char to sertch\n");
scanf("%s", cSearch);
*pInt = search_char( &cStr , &cSearch );
printf("Main prints here:\n");
for(i=0;i<20;i++){ //<== here problem starts
printf("%d\n",&pInt[i]);
return 0;
}

int search_char( char *pStr , char *pSearch ) {
printf("Funktion prints here:");
int i;
int vPossition[201];
for( i=0;i<=200;i++){
if(pStr[i] == pSearch[0]){
printf("Found %c in possition %d \n", pStr[i],i+1);
vPossition[i] = i; //<== here problem starts ????
}
}
return vPossition;//<== here problem starts ???
}

--

Thanx in advance
________________________
BTW. I know my english is not best in the word, so please stop bugging me
about my speling. And yes Iam sorry you don't understand what I mean, but
there is no point to yell at me. Have a nice day.

[August Karlstrom]

Carramba wrote:

hi!

Iam trying to make program were I enter string and serach char.
and funktion prints out witch position char is found this
is done if funktion serach_char. so far all good
what I want do next is:
return, from funktion, pointer value to array were
positions ( of found char) is stored. and print that array from main.
but I only manage to print memory adress to array..

any suggestions?

so far everything works fine.

int search_char( char *pStr , char *pSearch );

int main(void){
char cStr[201];
char cSearch[21];
int *pInt;
int i ;
printf("Enter string\n",lillae);
scanf("%s", cStr);
printf("Enter char to sertch\n");
scanf("%s", cSearch);
*pInt = search_char( &cStr , &cSearch );
printf("Main prints here:\n");
for(i=0;i<20;i++){ //<== here problem starts
printf("%d\n",&pInt[i]);
return 0;
}
Your code is poorly indented and the main function lacks the closing
brace, so the program won't compile.
int search_char( char *pStr , char *pSearch ) {
printf("Funktion prints here:");
int i;
Mixing statements and declarations of local variables is not allowed in
standard C.
int vPossition[201];
for( i=0;i<=200;i++){
if(pStr[i] == pSearch[0]){
printf("Found %c in possition %d \n", pStr[i],i+1);
vPossition[i] = i; //<== here problem starts ????
}
}
return vPossition;//<== here problem starts ???
}

-- August

(If your native tongue is not a western language I will be indulgent.)

[Carramba]

Your code is poorly indented and the main function lacks the closing
brace, so the program won't compile.

it's only copy and paste problem... so code ll compile

int search_char( char *pStr , char *pSearch ) {
printf("Funktion prints here:");
int i;

Mixing statements and declarations of local variables is not allowed in
standard C.

don't realy understand what you mean... were do I do that?

int vPossition[201];
for( i=0;i<=200;i++){
if(pStr[i] == pSearch[0]){
printf("Found %c in possition %d \n", pStr[i],i+1);
vPossition[i] = i; //<== here problem starts ????
}
}
return vPossition;//<== here problem starts ???
}

-- August

(If your native tongue is not a western language I will be indulgent.)

--

Thanx in advance
________________________
BTW. I know my english is not best in the word, so please stop bugging me
about my speling. And yes Iam sorry you don't understand what I mean, but
there is no point to yell at me. Have a nice day.

[August Karlstrom]

Carramba wrote:

Your code is poorly indented and the main function lacks the closing
brace, so the program won't compile.

it's only copy and paste problem... so code ll compile

int search_char( char *pStr , char *pSearch ) {
printf("Funktion prints here:");
int i;

Mixing statements and declarations of local variables is not allowed
in standard C.

don't realy understand what you mean... were do I do that?

Just before my comment. The `printf' statement comes before the `int i'
declaration. All local variables must be declared before any statements
in the function body.

For instance, you haven't included stdio.h and you haven't declared the
variable `lillae' in the `main' function so the program still won't
compile. What compiler are you using??? Come back when you have
something that compiles.
-- August

[Keith Thompson]

August Karlstrom <fu********@comhem.se> writes:

Carramba wrote:

[...]

int search_char( char *pStr , char *pSearch ) {
printf("Funktion prints here:");
int i;

Mixing statements and declarations of local variables is not allowed
in standard C.

It is allowed in C99. (It's also allowed in C++, which is relevant
only if you're using a C++ compiler to compile your C code, which is
usually a bad idea.)

It's also allowed as an extension by some compilers; for example,
"gcc -ansi" accepts it, but "gcc -ansi -pedantic" issues a warning.

But if you care about portability to pre-C99 implementations, you
should avoid using this feature.

And August is correct, the code you posted cannot be compiled. We
*might* be able to guess which errors are in your original code and
which are the result of cut-and-paste errors, but it should be much
easier for you to post your actual code than for us to play guessing
games. Proper indentation will make it much easier to read, and make
it much more likely that you'll get answers.

It may seem like we're being overly picky, but we're really not.
We're trying to help you to help us to help you.

--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.