In this complete tiny example, version one of an expression fails
----> theChar = *(currentMessage + characterNumber);
while my workaround expression version two succeeds.
----> theChar = (message[messageNumber])[characterNumber];
Both versions are fine on one C compiler and target but on another
version one fails. My understanding is that there should be no practical
difference, i.e. both should work.
- rob
# include <stdio.h>
const unsigned char *message[3] = {
"one message",
"second message",
"third and last maessage",
};
unsigned char *currentMessage;
unsigned char theChar;
unsigned char messageNumber, characterNumber;
unsigned char result;
int main(void)
{
result = 0;
/* version one */
currentMessage = (unsigned char *) message[1];
characterNumber = 2;
theChar = *(currentMessage + characterNumber);
if ('c' == theChar)
result |= 1;
/* version two */
messageNumber = 1;
characterNumber = 2;
theChar = (message[messageNumber])[characterNumber];
if ('c' == theChar)
result |= 2;
/* report */
printf("\n%d\n", result); /* should be 3, but is in fact 2 */
} 3 1088
ram wrote: In this complete tiny example, version one of an expression fails
----> theChar = *(currentMessage + characterNumber);
while my workaround expression version two succeeds.
----> theChar = (message[messageNumber])[characterNumber];
Both versions are fine on one C compiler and target but on another version one fails. My understanding is that there should be no practical difference, i.e. both should work.
- rob
# include <stdio.h>
const unsigned char *message[3] = { "one message", "second message", "third and last maessage", };
unsigned char *currentMessage; unsigned char theChar;
unsigned char messageNumber, characterNumber;
unsigned char result;
int main(void) { result = 0;
/* version one */
currentMessage = (unsigned char *) message[1]; characterNumber = 2;
theChar = *(currentMessage + characterNumber);
if ('c' == theChar) result |= 1;
/* version two */
messageNumber = 1; characterNumber = 2;
theChar = (message[messageNumber])[characterNumber];
if ('c' == theChar) result |= 2;
/* report */
printf("\n%d\n", result); /* should be 3, but is in fact 2 */ }
Using lcc-win32 I obtain 3...
On Mon, 7 Feb 2005, ram wrote: In this complete tiny example [snipped], version one of an expression fails while my workaround expression version two succeeds.
Both versions are fine on one C compiler and target but on another version one fails. My understanding is that there should be no practical difference, i.e. both should work.
That's my understanding also. However, the cast to 'unsigned char*'
is unnecessary and potentially dangerous once you start revising the
code; I suggest you remove it and see whether that magically fixes the
problem with the broken compiler. IOW, change
currentMessage = (unsigned char *) message[1];
to
currentMessage = message[1];
and change the definition of 'currentMessage' to
const unsigned char *currentMessage;
If that doesn't fix the problem, then I'd dismiss that compiler as
hopelessly broken --- unless of course someone else can point out
where you and I went wrong in our analyses!
HTH,
-Arthur
Arthur J. O'Dwyer wrote: That's my understanding also. However, the cast to 'unsigned char*' is unnecessary and potentially dangerous once you start revising the code; I suggest you remove it and see whether that magically fixes the problem with the broken compiler. IOW, change
currentMessage = (unsigned char *) message[1];
to
currentMessage = message[1];
and change the definition of 'currentMessage' to const unsigned char *currentMessage;
If that doesn't fix the problem, then I'd dismiss that compiler as hopelessly broken --- unless of course someone else can point out where you and I went wrong in our analyses!
Yes, that is exactly what I should have done and I will now spend some
time developing an understanding of this matter. Thanks!
--
rob This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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