I have initialized an array like this.
const char matrix[][] =
{
{0, 1, 2, 3},
{0, 1, 2},
{0, 1}
};
gcc, (with no options set,) errors unless I specify
const char matrix [][4] = ...
but at least one other compiler doesn't mind, and I'd rather not.
Can I assume the other compiler is divining the 4, and all members of matrix
will have length 4? If so, would this be an extension or a different
standard?
In either case, how would the unspecified members of matrix[1] and matrix[2]
be initialized?
Would referencing matrix[2][4], (not that I would,) be undefined?
I apologize for so many question marks in one post.
4  9667 
"Stephen Mayes" <st*********@themayeshouse.us> wrote in message
news:K4******************@bignews1.bellsouth.net.. . I have initialized an array like this.
const char matrix[][] =
{
{0, 1, 2, 3},
{0, 1, 2},
{0, 1}
};
gcc, (with no options set,) errors unless I specify
const char matrix [][4] = ...
but at least one other compiler doesn't mind, and I'd rather not.
Can I assume the other compiler is divining the 4, and all members of
matrix will have length 4? If so, would this be an extension or a
different standard?
In either case, how would the unspecified members of matrix[1] and
matrix[2] be initialized?
Would referencing matrix[2][4], (not that I would,) be undefined?
I apologize for so many question marks in one post.
OK. The compiler that allows the initialization without size subsequently
errors when I try to reference any members of matrix. 'unknown size of
incomplete array'...
So then I must specify the length of the largest array member?
Stephen Mayes wrote:
"Stephen Mayes" <st*********@themayeshouse.us> wrote in message
news:K4******************@bignews1.bellsouth.net.. .I have initialized an array like this.
const char matrix[][] =
{
{0, 1, 2, 3},
{0, 1, 2},
{0, 1}
};
gcc, (with no options set,) errors unless I specify
const char matrix [][4] = ...
but at least one other compiler doesn't mind, and I'd rather not.
Can I assume the other compiler is divining the 4, and all members of
matrix will have length 4? If so, would this be an extension or a
different standard?
In either case, how would the unspecified members of matrix[1] and
matrix[2] be initialized?
Would referencing matrix[2][4], (not that I would,) be undefined?
I apologize for so many question marks in one post.
OK. The compiler that allows the initialization without size subsequently
errors when I try to reference any members of matrix. 'unknown size of
incomplete array'...
So then I must specify the length of the largest array member?
You can only leave the left most brackets empty in an array declaration.
int array1[] = {0};
int array2[][1] = {0};
int array3[][1][1] = {0};
--
pete
pete wrote:
Stephen Mayes wrote:
"Stephen Mayes" <st*********@themayeshouse.us> wrote in message
news:K4******************@bignews1.bellsouth.net.. .I have initialized an array like this.
const char matrix[][] =
{
{0, 1, 2, 3},
{0, 1, 2},
{0, 1}
};
gcc, (with no options set,) errors unless I specify
const char matrix [][4] = ...
but at least one other compiler doesn't mind, and I'd rather not.
Can I assume the other compiler is divining the 4, and all members of
matrix will have length 4? If so, would this be an extension or a
different standard?
In either case, how would the unspecified members of matrix[1] and
matrix[2] be initialized?
Would referencing matrix[2][4], (not that I would,) be undefined?
I apologize for so many question marks in one post.
OK. The compiler that allows the initialization without size subsequently
errors when I try to reference any members of matrix. 'unknown size of
incomplete array'...
So then I must specify the length of the largest array member?
You can only leave the left most brackets empty in an array
declaration.
I suppose that should be "in an array initialization"
int array1[] = {0};
int array2[][1] = {0};
int array3[][1][1] = {0};
--
pete
--
pete
"pete" <pf*****@mindspring.com> wrote in message
news:41**********@mindspring.com... pete wrote:
Stephen Mayes wrote:
"Stephen Mayes" <st*********@themayeshouse.us> wrote in message
news:K4******************@bignews1.bellsouth.net.. .
>I have initialized an array like this.
>
> const char matrix[][] =
> {
> {0, 1, 2, 3},
> {0, 1, 2},
> {0, 1}
> };
>
> gcc, (with no options set,) errors unless I specify
> const char matrix [][4] = ...
> but at least one other compiler doesn't mind, and I'd rather not.
>
> Can I assume the other compiler is divining the 4, and all members
of > matrix will have length 4? If so, would this be an extension or a
> different standard?
>
> In either case, how would the unspecified members of matrix[1] and
> matrix[2] be initialized?
> Would referencing matrix[2][4], (not that I would,) be undefined?
>
> I apologize for so many question marks in one post.
>
>
OK. The compiler that allows the initialization without size
subsequently errors when I try to reference any members of matrix. 'unknown size
of incomplete array'...
So then I must specify the length of the largest array member?
You can only leave the left most brackets empty in an array
declaration.
I suppose that should be "in an array initialization"
Since we're being pedantic, make that
"array initializer", or "array initializer list".
-Mike This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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