Ruben <ru***@www2.mrbrklyn.com> wrote:
On Thu, 09 Sep 2004 14:32:51 -0400, Jens.Toerring wrote: Sorry, but the URL you gave for the code doesn't work.
Someone else said that you me but it seems to be working now. Covad was
having some troubles over at tellhouse this morning
https://www.freedom-it.com/clinical.tgz is up currently
Yep, got it now.
The main question
is: what exactly is it that you want to pass to the function? From what
you write it looks as if in the caller you have the 'value' array
defined as
char values[ N ][ 256 ];
where I don't know N but it doesn't really matter. If that is the case
then the form
char * insert(char table[255],int cols, char values[][256])
looks reasonable.
But it's not what I originally wanted. I'm quite sure and relooked at
old code on SCO and I used to just assign a char * to the address of the
array and then send it down as a single dimmensional array. This method
is dead appearently.
What exactly did you want? Please show a bit of real code, just describing
it in words tends to be too prone to misunderstandings.
The difference to the way argv is used is comes from
argv not being a 2-dimensional array but a 1-dimensional array of char
pointers. I.e. argv is defined similar to this
char *x[ M ];
OK
Each of the M pointers may point to a different string.
x is a pointer to an array of chars.
No, x is an array of char pointers. Only if x is used in value context,
i.e. it's treated as if it would have a value, like for example when
used in a function call, it gets converted in this context (it "decays
to" as it's often called, see also <http://web.torek.net/torek/c/pa.html>)
to a pointer to the first element of this array, i.e. a pointer to the
first char pointer - that's what the called function sees of it if it
gets called like "f( x );".
And that's not a
2-dimensional array - it only has room for M char pointers and nothing
more.
But where is it allocated memory for the pointer address?
Which pointer address?
All the strings pointed to must get their memory independently of
that definition
Yes. I was using strcpy of string literals for that. In my main gtk
program, they are coming from editable text objects.
Yes, but you're not working with an array of char pointers (like argv
is one) but with a two-dimensional array of chars (and that's why you
need to copy the strings and not just assign pointers to them).
If you now pass something like argv to a function what the function gets
is a pointer to the first element of this array, i.e. a pointer to the
first pointer - that's why argv can be written as either "char **argv"
or "char *argv[ ]" in the call of main().
On the other hand
char values[ N ][ 256 ];
has room for N strings, each 256 chars long. And it does not get
converted to a pointer to pointer when passed to a function, since it's
not a 1-dimensional array (what the function actually gets can be
treated as a pointer to the first char in the first string, so you could
define the function as
char * insert(char table[255],int cols, char *values)
I thought I tried this variation and it failed.
I'll give it another run.
Since in the caller you have
char *error;
char table[ ] = "patient";
char cols[ 3 ][ 256 ] = { { '\0' }, { '\0' }, { '\0' } };
strcpy( cols[ 0 ], patient.first );
strcpy( cols[ 1 ], patient.last );
strcpy( cols[ 2 ], patient.mrn );
error = insert( table, 3, cols );
the correct way to define the function, as far as I can see would be
char *insert( char table[ ], int cols, char values[ ][ 256 ] )
or
char *insert( char *table, int cols, char values[ ][ 256 ] )
(Please note that there isn't a 3 as the first dimension for
'values' here since it looks like you want to be able to get the
function to work with an unspecified number of strings, otherwise
you wouldn't have to pass the number if strings in the 'cols'
variable to the function. And there's also no explicit size for
the length of 'table' since you don't know in advance, it's definitely
not 255. Finally, in your insert_patient() function you use the type
'gchar' for 'table' and '*error' but your insert() function expects
and returns 'char', which doesn't look right.)
Since you don't seem to change neither 'table' nor any of the strings
from 'values' within the insert() function it might make sense to
make that clear by using
char *insert( const char *table, int cols, const char values[ ][ 256 ] )
And if this will stay that way (i.e. none of the strings is ever going
to be changged from within insert()) you could even get rid of copying
all that strings from the 'patient' structure to the 'cols' matrix.
You could use an array of char pointers here and just do
char *error;
char *table = "patient";
char *cols[ ] = { patient.first, patient.last, patient,mrn };
error = insert( table, sizeof cols / sizeof *cols, cols );
Then you would have to define the insert() function as
char *insert( const char *table, int cols, const char *cols[ ] );
i.e. use the same method by which argv is passed to main(). In that
case the 'cols' in insert() would be an array of char pointers, each
pointing to a string (you're not supposed to modify).
BTW, your insert() function is badly leaking memory - you call malloc()
twice there without ever freeing the memory you got. And, of course,
you should check the return value of malloc() and not blindly assume
that it did succeed. Actually, the 'value' array, for which you also
allocate memory is never used at all. Moreover, this part
strcpy( query,"INSERT INTO " );
strcat( query, table );
strcat( query, " VALUES (NULL,'" );
str_length = strlen( query );
end = query + str_length;
str_length = strlen( query );
end = query + str_length;
looks strange - the two last lines look wrong because they make 'end'
point way beyond the end of the 'query' string. Actually, you could
do all you need to do in a single line, i.e.
end = query + sprintf( query, "INSERT INTO %s VALUES (NULL,'", table );
Also the following code won't work correctly:
for ( i = 0; i < cols; i++ )
{
end += mysql_real_escape_string( clinical_db, end, values[ i ],
strlen( values[ i ] ) );
*end++ = '\'';
*end++ = ',';
*end++ = '\'';
}
str_length = strlen( end ) - 2;
end[ str_length ] = ')';
str_length++;
end[ str_length ] = '\0';
If you get out of that loop, 'end' doesn't point to a '\0' terminated
string, so applying strlen() to it won't work. All you actually need
here is
*( end - 2 ) = ')';
*( end - 1 ) = '\0';
Regards, Jens
--
\ Jens Thoms Toerring ___
Je***********@physik.fu-berlin.de
\__________________________
http://www.toerring.de 
