#include<stdio.h>
void main()
{
int a=0,b=6,c=7,d=8,e;
e = a ? c , b : c , d;
printf("%d",e);
}
o/p->7 6 1255
Sweety wrote:
[crap indicating that "Sweety" never checks a FAQ, never checks past
traffic in a news group, never has read a non-Schildt textbook on C; or
else is just trolling.]
Go away.
On Mon, 26 Jul 2004 17:30:03 +0000, Martin Ambuhl wrote: Sweety wrote:
[crap indicating that "Sweety" never checks a FAQ, never checks past traffic in a news group, never has read a non-Schildt textbook on C; or else is just trolling.]
I don't quite get the output of his programm either. I changed it a bit,
and got similar output I don't quite understand.
I did the following
#include <stdio.h>
int main(void) {
int e;
e= 0 ? 1,2 : 3,4;
printf("%d", e);
return 0;
}
I get the output 3, however I think it should be for, no matter in which
order you evaluate. I also did the following:
#include <stdio.h>
int main(void) {
int e;
e= (0 ? 1,2 : 3),4;
printf("%d", e);
return 0;
}
// Output: 3
and:
#include <stdio.h>
int main(void) {
int e;
e= 0 ? (1,2) : (3,4);
printf("%d", e);
return 0;
}
// output 4
and even:
#include <stdio.h>
int main(void) {
int e;
(e= 0 ? 1,2 : 3),4;
printf("%d", e);
return 0;
}
// Output 3
Is it correct that the comma operator takes even less precedence than the
= operator?
Till
--
Please add "Salt and Peper" to the subject line to bypass my spam filter
On Tue, 27 Jul 2004, Till Crueger wrote: I don't quite get the output of his programm either. I changed it a bit, and got similar output I don't quite understand. I did the following
#include <stdio.h>
int main(void) { int e; e= 0 ? 1,2 : 3,4; printf("%d", e); return 0; }
I get the output 3, however I think it should be for, no matter in which order you evaluate. I also did the following:
[snip]
Is it correct that the comma operator takes even less precedence than the = operator?
According to the C syntax, the above expression should be
parsed as follows:
(1) expression:
expression , assignment-expr
e= 0 ? 1,2 : 3 , 4
(2) expression:
assignment-expr:
unary-expr assignment-operator assignment-expr
e = 0 ? 1,2 : 3
(3) assignment-expr:
conditional-expr:
logical-OR-expr ? expression : conditional-expr
0 ? 1,2 : 3
(4) expression:
expression , assignment-expr
1 , 2
Therefore the output 3 is correct.
Tak-Shing
"Till Crueger" <Ti****@gmx.net> wrote: I don't quite get the output of his programm either. I changed it a bit, and got similar output I don't quite understand. I did the following
#include <stdio.h>
int main(void) { int e; e= 0 ? 1,2 : 3,4; printf("%d", e); return 0; }
I get the output 3, however I think it should be for, no matter in which order you evaluate.
The assignment operator has higher precedence than the comma operator. The
line is parsed like this:
(e = 0 ? 1,2 : 3), 4;
That is, first e is assigned the value 3, then the statement has the value
4.
--
Simon.
Thanks all who have useful reply rather than this ?
Martin Ambuhl <ma*****@earthlink.net> wrote in message news:<2m************@uni-berlin.de>... Sweety wrote:
[crap indicating that "Sweety" never checks a FAQ, never checks past traffic in a news group, never has read a non-Schildt textbook on C; or else is just trolling.]
Go away. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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