printf on matrix...

[Bilbo]

Hello!

I have a matrix type of variable, lets call it matrix[2][3]...can I see on
screen it via printf?? how??

Thanks

[jota]

> I have a matrix type of variable, lets call it matrix[2][3]...can I see on

screen it via printf?? how??

for(int n=0;n<2;n++)
for(int m=0;m<3;m++)
printf("matrix[%d][%d]=%d\n",n,m,matrix[n][m]);

//jota

[Lewis Bowers]

Bilbo wrote:

Hello!

I have a matrix type of variable, lets call it matrix[2][3]...can I see on
screen it via printf?? how??

I would put the printf in nested for loops.
Here is an example of type integer.

#include <stdio.h>

int main(void)
{
int i,j,matrix[2][3] = {{1,2,3},{4,5,6}};
for(i = 0; i < 2; i++)
{
for(j = 0;j < 3; j++)
printf("%-6d",matrix[i][j]);
putchar('\n');
}
return 0;
}

[E. Robert Tisdale]

Lewis Bowers wrote:

Bilbo wrote:

I have a matrix type of variable, lets call it matrix[2][3]...
can I see on screen it via printf? How?

I would put the printf in nested for loops.
Here is an example of type integer.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char* argv[]) {
int matrix[2][3] = {{1, 2, 3}, {4, 5, 6}};
for(size_t i = 0; i < 2; ++i) {
for(size_t j = 0; j < 3; ++j)
printf("%-6d", matrix[i][j]);
putchar('\n');
}
return EXIT_SUCCESS;
}

#include <stdlib.h>
#include <stdio.h>

int matrix_fprintf(FILE* fp, const char* format,
size_t m, size_t n, int matrix[m][n]) {
int characters = 0;
for(size_t i = 0; i < m; ++i) {
for(size_t j = 0; j < n; ++j)
characters += fprintf(fp, format, matrix[i][j]);
characters += fprintf(fp, "\n");
}
return characters;
}

int main(int argc, char* argv[]) {
int matrix[2][3] = {{1, 2, 3}, {4, 5, 6}};
matrix_fprintf(stdout, " %6d", 2, 3, matrix);
return EXIT_SUCCESS;
}