Hey gang,
So I have my stdin which is user defined file, and am wanting to write
it to a temporary file (seems odd I know, but there is a sincere
reason), and then use that file as the stdin for the remaining part of
the program. I have combed the FAQ and got some preliminary questions
answered, and tried to model this after what I have seen suggested to
people previously, but for my strcpy and freopen I get,
"warning: passing arg 1 of `strcpy' from incompatible pointer type"
and
"warning: passing arg 1 of `freopen' from incompatible pointer type".
#include <stdio.h>
#include <string.h>
FILE *tempfile;
char s[L_tmpnam];
strcpy(tempfile, tmpnam(s));
/*tempfile = stdout; */
do{
. . .
for (i=0;i<istat;i++) floatarray[i] = (float) dfloatarray[i];
iostat = fwrite(floatarray,4,istat,tempfile);
if (iostat != istat) fprintf(stderr, "Failed on writing to temporary
file.");
} while(feof(stdin) == 0);
freopen(tempfile,"r",stdin);
But it doesn't have a problem w/ tempfile as arg 4 of fwrite? As you
can see, I have tried setting the tempfil as stdout, but that doesn't
change my error message. Any thoughts? Thanks as always!
JMW 1 2847
Josh Wilson wrote: Hey gang,
So I have my stdin which is user defined file, and am wanting to write it to a temporary file (seems odd I know, but there is a sincere reason), and then use that file as the stdin for the remaining part of the program. I have combed the FAQ and got some preliminary questions answered, and tried to model this after what I have seen suggested to people previously, but for my strcpy and freopen I get, "warning: passing arg 1 of `strcpy' from incompatible pointer type" and "warning: passing arg 1 of `freopen' from incompatible pointer type".
#include <stdio.h> #include <string.h> FILE *tempfile; char s[L_tmpnam];
strcpy(tempfile, tmpnam(s));
This line is evidence that you have no understanding
of what a FILE* is for.
A FILE* points to a piece of implementation magic
that somehow keeps track of an I/O stream. The details
of how this is done are none of your business; you are
not to look too closely at the magic. Meddle not in
the affairs of implementors, for they are subtle and
quick to undefined behavior.
The way you associate a FILE* stream with a given
file name is to use the fopen() function. You do *not*
try to blast the file name's characters onto the magical
object to which the FILE* points. Just Say No.
/*tempfile = stdout; */ do{ . . . for (i=0;i<istat;i++) floatarray[i] = (float) dfloatarray[i]; iostat = fwrite(floatarray,4,istat,tempfile); if (iostat != istat) fprintf(stderr, "Failed on writing to temporary file."); } while(feof(stdin) == 0); freopen(tempfile,"r",stdin);
Repeat after me: A FILE* is not a file name. Write
this on the blackboard one hundred times, and then revisit
this line of code.
But it doesn't have a problem w/ tempfile as arg 4 of fwrite?
Why should it? fwrite() expects to receive a FILE* as
its fourth argument.
As you can see, I have tried setting the tempfil as stdout, but that doesn't change my error message. Any thoughts?
Thought: You really need to review C's I/O capabilities,
because the evidence suggests you don't yet understand them.
You are not yet ready to write this program.
-- Er*********@sun.com This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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