time function not defined?

[Greg]

I am using the following code to try and output the current date and
time in a C program.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// global variables

struct tm *currentTime ;

int main (void) {
char *time ;

time_t time_now = time (NULL) ;

currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Anyone know why the time function is not working for me?

Thanks

Greg

[Régis Troadec]

"Greg" <dj*********@snowboard.com> a écrit dans le message de
news:7e**************************@posting.google.c om...

Hi,

[snipped]

int main (void) {
char *time ;

time_t time_now = time (NULL) ;
Take a closer look at the two lines above and you'll get the answer.
currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Anyone know why the time function is not working for me?
Yes, you declared a pointer to a char named time, which *is in conflict with
the name* of the time() function of the standard library.

Regis
Thanks

Greg

[P.J. Plauger]

"Greg" <dj*********@snowboard.com> wrote in message
news:7e**************************@posting.google.c om...

I am using the following code to try and output the current date and
time in a C program.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// global variables

struct tm *currentTime ;

int main (void) {
char *time ; ^^^^ local redefinition of time
time_t time_now = time (NULL) ; ^^^^ library function is masked
currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Anyone know why the time function is not working for me?

The compiler is telling you. See comments above.

P.J. Plauger
Dinkumware, Ltd.
http://www.dinkumware.com

[Huilong Huang]

Hi, Greg,

You defined a variable " char *time ", which has the same name of the
function time(), hence when you refer the name "time", it actually refers to
the variable "char *time" in that scope.

Huilong
"Greg" <dj*********@snowboard.com> wrote in message
news:7e**************************@posting.google.c om...

I am using the following code to try and output the current date and
time in a C program.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// global variables

struct tm *currentTime ;

int main (void) {
char *time ;

time_t time_now = time (NULL) ;

currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Anyone know why the time function is not working for me?

Thanks

Greg

[Martin Ambuhl]

Greg wrote:

I am using the following code to try and output the current date and
time in a C program.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// global variables

struct tm *currentTime ;

int main (void) {
char *time ; ^^^^
You have changed 'time' from referring to a function to referring to a
pointer-to-char.
time_t time_now = time (NULL) ; ^^^^
The pointer-to-char identifier 'time' is not a function name in this scope.

currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Obviously. pointers-to-char are not functions.

[Keith Thompson]

dj*********@snowboard.com (Greg) writes:

I am using the following code to try and output the current date and
time in a C program.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// global variables

struct tm *currentTime ;

int main (void) {
char *time ;

time_t time_now = time (NULL) ;

currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Anyone know why the time function is not working for me?

Several other people have told you that the problem is your
redefinition of "time" as a char* variable. But for future reference,
if you post a code sample and an error message that indicates a line
number, let us know where line 12 really is. The line containing the
call to time() is actually the 13th line of the code you posted.

--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
Schroedinger does Shakespeare: "To be *and* not to be"

[Dan Pop]

In <7e**************************@posting.google.com > dj*********@snowboard.com (Greg) writes:

I am using the following code to try and output the current date and
time in a C program.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

// global variables

struct tm *currentTime ;

int main (void) {
char *time ;

time_t time_now = time (NULL) ;

currentTime = localtime (&time_now) ;
}

When I compile this I get the following:

time.c: In function `main':
time.c:12: called object is not a function

Anyone know why the time function is not working for me?

In C, object names share the same name space with function names.
When you declared time as a char pointer in main, you have suppressed the
declaration of time coming from <time.h> until the end of the block
containing the new declaration (i.e. until the end of the function main
in your case).

IOW, you have shot yourself in the foot.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de