Char const for backslash

[Sathyaish]

In trying to replace character literals for their char constant, I am
having difficulty printing the char constant for backslash. It instead
prints the char literal. How do I resovle this?
#include <stdio.h>

/*A program that reads keyboard input and reproduces it on the monitor
with some modifications.
It displays all newline character occurences as \n, tabs as \t and
backslashes as \\.

Basically, it replaces some of the characters with their character
constants.

*/

void main()
{
int c;

while ((c=getchar()) != EOF)
{

if ((char)c=='\n')
{
printf("\\n");
putchar(c);
}
else if ((char)c=='\t')
{
printf("\\t");
}
else if ((char)c=='\\')
{
printf("\\");
}
else
{
putchar(c);
}

} //end of while loop

} // end of main
I want that when I type a backslash, the output must be replaced with
\\, the character constant for backslash.

[Joona I Palaste]

Sathyaish <Vi****************@yahoo.com> scribbled the following:

In trying to replace character literals for their char constant, I am
having difficulty printing the char constant for backslash. It instead
prints the char literal. How do I resovle this?

Try printf("\\\\").

--
/-- Joona Palaste (pa*****@cc.helsinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
"Normal is what everyone else is, and you're not."
- Dr. Tolian Soran

[Martin Dickopp]

Vi****************@yahoo.com (Sathyaish) writes:

In trying to replace character literals for their char constant, I am
having difficulty printing the char constant for backslash. It instead
prints the char literal. How do I resovle this?
#include <stdio.h>

/*A program that reads keyboard input and reproduces it on the monitor
with some modifications.
It displays all newline character occurences as \n, tabs as \t and
backslashes as \\.

Basically, it replaces some of the characters with their character
constants.

*/

void main()
int main (void)
{
int c;

while ((c=getchar()) != EOF)
{

if ((char)c=='\n')
Why do you cast `c' to `char'? It's completely unnecessary. Before it is
compared to the `int' constant '\n', the result of `(char)c' is promoted
to `int' anyway.
else if ((char)c=='\\')
{
printf("\\");

\\ in a string or character literal represents a single \, so "\\" is a
string literal consisting of a single backslash character. You want
"\\\\".

Martin
--
,--. Martin Dickopp, Dresden, Germany ,= ,-_-. =.
/ ,- ) http://www.zero-based.org/ ((_/)o o(\_))
\ `-' `-'(. .)`-'
`-. Debian, a variant of the GNU operating system. \_/

[Sathyaish]

Thank you very much, Joona and Martin. You're so right.

Regards,
Sathyaish Chakravarthy.

Martin Dickopp <ex****************@zero-based.org> wrote in message news:<cu*************@zero-based.org>...

Vi****************@yahoo.com (Sathyaish) writes:

In trying to replace character literals for their char constant, I am
having difficulty printing the char constant for backslash. It instead
prints the char literal. How do I resovle this?
#include <stdio.h>

/*A program that reads keyboard input and reproduces it on the monitor
with some modifications.
It displays all newline character occurences as \n, tabs as \t and
backslashes as \\.

Basically, it replaces some of the characters with their character
constants.

*/

void main()

int main (void)

{
int c;

while ((c=getchar()) != EOF)
{

if ((char)c=='\n')

Why do you cast `c' to `char'? It's completely unnecessary. Before it is
compared to the `int' constant '\n', the result of `(char)c' is promoted
to `int' anyway.

else if ((char)c=='\\')
{
printf("\\");

\\ in a string or character literal represents a single \, so "\\" is a
string literal consisting of a single backslash character. You want
"\\\\".

Martin