Who can explain the sentence for me?

[huhu]

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?
Thanks!

[Servé Lau]

"huhu" <as***@public.gz.cn> wrote in message
news:c1**********@mail.cn99.com...

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?

an array of function pointers is declared and initialized. The functions
have a struct intNode * as return value and expect no parameters.

[jacob navia]

"huhu" <as***@public.gz.cn> a écrit dans le message de
news:c1**********@mail.cn99.com...

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?
Thanks!

fpt is a table of functions that return a pointer to an "intNode" and
receive no arguments. This table contains 5 positions, the first four are
filled with the
respective functions, and the fifth position is NULL.

C can be very concise. More probably than is needed... :-)

[anonymous]

"huhu" <as***@public.gz.cn> wrote in message

Who can explain it for me?

*cdecl* (C declaration parser) can explain it for you.

[Barry Schwarz]

On Sun, 29 Feb 2004 20:16:43 +0800, "huhu" <as***@public.gz.cn> wrote:

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?
Thanks!

fpt is a 1-D array of unspecified quantity of pointer to function
(each of the functions pointed to be elements of the array)
taking no parameters
returning pointer to struct intNode

The array is initialized with five values (and the unspecified
quantity mentioned above is now determined to be five):
the address of the function createList
the address of the function inNode
....
the value of the NULL pointer constant
<<Remove the del for email>>

[Dan Pop]

In <c1**********@news-reader3.wanadoo.fr> "jacob navia" <ja***@jacob.remcomp.fr> writes:

"huhu" <as***@public.gz.cn> a écrit dans le message de
news:c1**********@mail.cn99.com...

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?
Thanks!

fpt is a table of functions that return a pointer to an "intNode" and
receive no arguments. This table contains 5 positions, the first four are
filled with the
respective functions, and the fifth position is NULL.

C can be very concise. More probably than is needed... :-)

^^^^^^^^^^^^^^^^^^^^^^^^^^^^
That's one of the reasons it comes with the typedef thing :-)

A single typedef could turn that monster declaration into something
that even a beginner could read.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de

[Alex Monjushko]

huhu <as***@public.gz.cn> wrote:

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?
Thanks!

There is no such thing as a sentence in C.

'fpt' is defined as an array of pointers to functions which take
no arguments and return a pointer to 'struct intNode'. It is
subsequently initialized with what are probably pointers to
functions that meet these critera.

I recommend that you consult your favorite C book.

--
Alex Monjushko (mo*******@hotmail.com)

[John Bode]

"huhu" <as***@public.gz.cn> wrote in message news:<c1**********@mail.cn99.com>...

Hi,
I meet a sentence:
------------------------------------------------
struct intNode *(*fpt[])(void)=
{createList, inNode, delNode,revNode,NULL};
-------------------------------------------------
The "createList","inNode","delNode","revNode" are functions.
I'm puzzled by the c sentence.
Who can explain it for me?
Thanks!

fpt -- fpt
fpt[] -- is an array
*fpt[] -- of pointers
(*fpt[])() -- to functions
(*fpt[])(void) -- taking no parameters
*(*fpt[])(void) -- returning pointers
struct intNode *(*fpt[])(void) -- to struct intNode

and the prototypes for the functions in the array are

struct intNode *createList (void);
struct intNode *inNode (void);
struct intNode *delNode (void);
struct intNode *revNode (void);

Calling fpt[0]() is the same as calling createList(), fpt[1]() is the
same as calling inNode(), etc.

[huhu]

Thank you very much!