string assign to multi-dimension array w/o using pointer.

[Makiyo]

how do u do something like this
char x[3][10];
x[0][] = "hello";

I got an error,
but is there a way I can do it without using pointer?
thx ; )

[David Rubin]

Makiyo wrote:

how do u do something like this
char x[3][10];
x[0][] = "hello";

I got an error,
but is there a way I can do it without using pointer?
thx ; )

strcpy(x[0], "hello");

/david

--
"As a scientist, Throckmorton knew that if he were ever to break wind in
the echo chamber, he would never hear the end of it."

[Russell Hanneken]

Makiyo wrote:

how do u do something like this
char x[3][10];
x[0][] = "hello";

I got an error,
but is there a way I can do it without using pointer?

I guess you're trying to do this:

char x[3][10];
strcpy(x[0], "hello");

You can also initialize the array like this:

char x[3][10] = { "hello" }; /* Because initializers are missing for
x[1] and x[2], 0 is assigned to
every element of both arrays */
--
Russell Hanneken
rg********@pobox.com
Remove the 'g' from my address to send me mail.

[Richard Heathfield]

Makiyo wrote:

how do u do something like this
char x[3][10];
x[0][] = "hello";

I got an error,
That's because you can't assign to an array. x[0] is an array of 10 char,
and an array is not a "modifiable lvalue" (I'll spare you the details), so
you can't do what you tried to do.
but is there a way I can do it without using pointer?

No. Any attempt to load x[0] involves using a pointer, although I'll agree
that it doesn't always /look/ like it. This is because of The Rule.

strcpy(x[0], "hello"); will work fine, for example, but it does actually use
a pointer (because of The Rule).

--
Richard Heathfield : bi****@eton.powernet.co.uk
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