Hello
I am facing a weired problem in calling a fortran routine from
c. The fortran function in question is like this:-
subroutine fortran_fun(idtab, nx, x, nf, nh, nhd, info, rinfo, fa,
ga, ha, stats,iusr_size, iusr,rusr_size, rusr )
implicit none
external usrfgh
external foo
integer :: idtab, nx, nf, nh, nhd, info(20),itno
integer :: iusr_size, rusr_size
integer :: iusr(iusr_size)
doubleprecision :: x(nx), rinfo(20+nx+nf)
doubleprecision :: fa(nf), ha(nhd), stats(50)
doubleprecision :: ga(nf,nx)
doubleprecision :: rusr(rusr_size)
character*128 :: fn
............
............
While calling this function from another c with debugger
attached, gdb output is:-
fortran_fun (idtab=13, nx=2, x=(), nf=1, nh=0, nhd=1, info=(0, 0, 0,
1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0), rinfo=(), fa=(),
ga=(), ha=(), stats=Cannot access memory at address 0x0
) at isat_wrap.f90:8
the varible *stats* is a pointer of _double_(fortran real*8 =
c double) type and points to 50 valid blocks of memory allocated in C.
(i have checkd it in c side and it is not NULL). It seems that the
satck gets corrupted while calling the fortran function. How can I
proceed? I am using gcc 3.2 and intel fortran compiler.
Any help is welcome.
Thanks in advance
Pavan
