Error in Preprocessing

[Naren]

Hello,

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler

#include <stdio.h>

#define PP 1,2,3,4

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )

#define PP_Val PP_Func(PP)

int main()

{

printf ("\n%d", PP_Val );

return 0;

}

Thanks in advance,

Regards,

Naren.

[pete]

Naren wrote:

Hello,

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler

#include <stdio.h>

#define PP 1,2,3,4
That's the same as

#define PP (1,2,3,4)

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )

#define PP_Val PP_Func(PP)
#define PP_Val PP_Func(PP, PP, PP, PP)
int main()

{

printf ("\n%d", PP_Val );

return 0;

}

--
pete

[Dan Pop]

In <bv**********@ns2.fe.internet.bosch.com> "Naren" <na*************@in.bosch.com> writes:

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler

#include <stdio.h>

#define PP 1,2,3,4

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )

#define PP_Val PP_Func(PP) ^^^^^^^^^^^^^^^^^^^^^^^^^^
Replace this line by:

#define XPP_Func(arg) PP_Func(arg)
#define PP_Val XPP_Func(PP)

Otherwise, PP_Func will be invoked with PP as argument, instead of its
expansion.
int main()

{

printf ("\n%d", PP_Val );

return 0;

}

When the argument of a macro is another macro, you need an extra level
of macro expansion, so that the target macro is invoked with the
macro argument expanded. This is also explained in the FAQ.

After making the change suggested above and removing the include line
(it is necessary for the program correctness, but not if the program is
only preprocessed, as it will generate tons of preprocessor output),
the preprocessor generates the following output:

fangorn:~/tmp 223> cat test.c
#define PP 1,2,3,4
#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )
#define XPP_Func(arg) PP_Func(arg)
#define PP_Val XPP_Func(PP)

int main()
{
printf ("\n%d", PP_Val );
return 0;
}
fangorn:~/tmp 224> gcc -ansi -E test.c
# 1 "test.c"
# 1 "<built-in>"
# 1 "<command line>"
# 1 "test.c"

int main()
{
printf ("\n%d", ( ((1)*1) + ((2) * 2) +((3) * 3) + ((4) * 4) ) );
return 0;
}

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de

[Dan Pop]

In <40***********@mindspring.com> pete <pf*****@mindspring.com> writes:

Naren wrote:

Hello,

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler

#include <stdio.h>

#define PP 1,2,3,4

That's the same as

#define PP (1,2,3,4)

Nonsense.

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )

#define PP_Val PP_Func(PP)

#define PP_Val PP_Func(PP, PP, PP, PP)

More nonsense.

int main()

{

printf ("\n%d", PP_Val );

return 0;

}

With your suggestion, the printf call expands to:

printf ("\n%d", ( ((1,2,3,4)*1) + ((1,2,3,4) * 2) +((1,2,3,4) * 3) + ((1,2,3,4) * 4) ) );

Syntactically correct, but obviously not what the OP wanted.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de

[Martin Ambuhl]

Naren wrote:

Hello,

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler
The compiler should not be relevant.
#include <stdio.h>
#define PP 1,2,3,4
#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )
#define PP_Val PP_Func(PP)
PP_Func is defined as taking 4 arguments, and you are using it with one.
int main()
{
printf ("\n%d", PP_Val );
return 0;
}

Thanks in advance,

--
Martin Ambuhl

[Peter Nilsson]

pete <pf*****@mindspring.com> wrote in message news:<40***********@mindspring.com>...

Naren wrote:

Hello,

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler

#include <stdio.h>

#define PP 1,2,3,4
That's the same as

#define PP (1,2,3,4)

This is highly misleading. It's not the same at all.

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )

#define PP_Val PP_Func(PP)
The critical point to note is that PP is not substituted immediately
in subsequent macro _definitions_. Nor is it substituted immediately
on subsequent _usage_ of PP_Val [because it is not a macro parameter
to PP_Val.]
#define PP_Val PP_Func(PP, PP, PP, PP)

This won't do what I imagine the OP wants to do.
int main()

{
printf ("\n%d", PP_Val );
return 0;
}

#include <stdio.h>

#define PP 1,2,3,4

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) *
4) )

#define Val(PP) PP_Func(PP)

int main()
{
printf ("\n%d", Val(PP) );
return 0;
}

The expansion of Val(PP) within the printf is...

Val(PP) -> PP_Func(PP) -> PP_Func(1,2,3,4) -> ...

The obvious kludgy-ness of this would be good reason to rethink the
stratagy of defining a comma delimited parameter list as a macro.

--
Peter

[pete]

Dan Pop wrote:

In <40***********@mindspring.com> pete <pf*****@mindspring.com> writes:

Naren wrote:

Hello,

Could anyone explain why I get an error
when I compile this in MSVC6.0 compiler

#include <stdio.h>

#define PP 1,2,3,4

That's the same as

#define PP (1,2,3,4)

Nonsense.

Thank you.

--
pete

[Naren]

> #define PP 1,2,3,4

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) ) #define XPP_Func(arg) PP_Func(arg)
#define PP_Val XPP_Func(PP)

int main()
{
printf ("\n%d", PP_Val );
return 0;
}

When I compile this in MSVC6.0 I get this error
NewPreProcesor.c
f:\casc\newpre\newpreprocesor.c(8) : warning C4013: 'printf' undefined;
assuming extern returning int
f:\casc\newpre\newpreprocesor.c(8) : warning C4003: not enough actual
parameters for macro 'PP_Func'
f:\casc\newpre\newpreprocesor.c(8) : error C2059: syntax error : ')'>

Thanks in advance
Regards,
Naren.

[Zoran Cutura]

Naren <na*************@in.bosch.com> wrote:

Hello,

Could anyone explain why I get an error when I compile this in MSVC6.0
compiler

#include <stdio.h>

#define PP 1,2,3,4

#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) * 4) )

#define PP_Val PP_Func(PP)

int main()

{

printf ("\n%d", PP_Val );

return 0;

}

Here we go... PP_Val is invoked, that is its text is replaced by the
text it is defined with. That is PP_Func(PP) will be inserted instead.
The preprocessor again checks if there are further prepocessor
invocations and it finds PP_Func to be invoked which is a functions like
mcaro and expects 4 arguments. But instead of four it is passed exactly
one argument which is PP, so it will give you some diagnostic.

--
Z (Zo**********@daimlerchrysler.com)
"LISP is worth learning for the profound enlightenment experience
you will have when you finally get it; that experience will make you
a better programmer for the rest of your days." -- Eric S. Raymond

[Peter Shaggy Haywood]

Groovy hepcat Naren was jivin' on Fri, 30 Jan 2004 19:16:43 +0530 in
comp.lang.c.
Re: Error in Preprocessing's a cool scene! Dig it!

#define PP 1,2,3,4
#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) *

4) )

#define XPP_Func(arg) PP_Func(arg)
#define PP_Val XPP_Func(PP)

int main()
{
printf ("\n%d", PP_Val );
return 0;
}

When I compile this in MSVC6.0 I get this error
NewPreProcesor.c
f:\casc\newpre\newpreprocesor.c(8) : warning C4013: 'printf' undefined;
assuming extern returning int
f:\casc\newpre\newpreprocesor.c(8) : warning C4003: not enough actual
parameters for macro 'PP_Func'
f:\casc\newpre\newpreprocesor.c(8) : error C2059: syntax error : ')'>

Then you must have done something wrong, because the only diagnostic
message I get is this, which is very understandable:

testing.c(10): Warning! W301: No prototype found for 'printf'

(You goofed on this one, Dan.)
Naren, you must have (mis)typed the program into your programming
editor instead of copying and pasting. Had you done the latter, then
you would, no doubt, have seen the same results as I did.

--

Dig the even newer still, yet more improved, sig!

http://alphalink.com.au/~phaywood/
"Ain't I'm a dog?" - Ronny Self, Ain't I'm a Dog, written by G. Sherry & W. Walker.
I know it's not "technically correct" English; but since when was rock & roll "technically correct"?

[Paul Mensonides]

Peter "Shaggy" Haywood wrote:

When I compile this in MSVC6.0 I get this error
NewPreProcesor.c
f:\casc\newpre\newpreprocesor.c(8) : warning C4013: 'printf'
undefined; assuming extern returning int
f:\casc\newpre\newpreprocesor.c(8) : warning C4003: not enough actual
parameters for macro 'PP_Func'
f:\casc\newpre\newpreprocesor.c(8) : error C2059: syntax error : ')'>

Then you must have done something wrong, because the only diagnostic
message I get is this, which is very understandable:

testing.c(10): Warning! W301: No prototype found for 'printf'

(You goofed on this one, Dan.)
Naren, you must have (mis)typed the program into your programming
editor instead of copying and pasting. Had you done the latter, then
you would, no doubt, have seen the same results as I did.

Not necessarily. VC6 through the most current version fails to implement macro
replacement in the order defined by the standard. VC will fail this test every
time:

#define ARGS 1, 2

#define A(args) B(args)
#define B(x, y) x + y

A(ARGS)

Regards,
Paul Mensonides

[Dan Pop]

In <40***************@news.australis.net> sh****@australis.net.STOP.SPAM (Peter "Shaggy" Haywood) writes:

Groovy hepcat Naren was jivin' on Fri, 30 Jan 2004 19:16:43 +0530 in
comp.lang.c.
Re: Error in Preprocessing's a cool scene! Dig it!

#define PP 1,2,3,4
#define PP_Func(x,y,z,w) ( ((x)*1) + ((y) * 2) +((z) * 3) + ((w) *

4) )

#define XPP_Func(arg) PP_Func(arg)
#define PP_Val XPP_Func(PP)

int main()
{
printf ("\n%d", PP_Val );
return 0;
}

When I compile this in MSVC6.0 I get this error
NewPreProcesor.c
f:\casc\newpre\newpreprocesor.c(8) : warning C4013: 'printf' undefined;
assuming extern returning int
f:\casc\newpre\newpreprocesor.c(8) : warning C4003: not enough actual
parameters for macro 'PP_Func'
f:\casc\newpre\newpreprocesor.c(8) : error C2059: syntax error : ')'>

Then you must have done something wrong, because the only diagnostic
message I get is this, which is very understandable:

testing.c(10): Warning! W301: No prototype found for 'printf'

(You goofed on this one, Dan.)

Are you reading impaired or what? From my previous post:

After making the change suggested above and removing the include line
(it is necessary for the program correctness, but not if the program is
only preprocessed, as it will generate tons of preprocessor output),
the preprocessor generates the following output:

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de