I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
TIA.
--
main(){char s[37]="CSbwjAjocpy/mw!PS!sbwjAeftqbnnfe/dpn";
int i;for(i=0;i<36;putchar(s[i++]-1));return 0;}
9  7055 
On Sun, 09 Nov 2003 23:22:55 +0530, Ravi wrote: I hope this is not a FAQ.
printf("%%%%");
What is the output for this?
"%%%%"
Is it implementation dependent?
no, AFAIK
On Sun, 09 Nov 2003 23:22:55 +0530, Ravi wrote: I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
TIA.
If you don't have a book that covers this sort of thing, go buy
one as soon as possible. ok?
In the meantime, here are some excerpts from the standard:
ISO/IEC 9899:1999 (E)
7.19.6.1
4 Each conversion specification is introduced by the character %.
8 The conversion specifiers and their meanings are:
% - A % character is written. No argument is converted. The complete
conversion specification shall be %%.
On Mon, 10 Nov 2003 05:08:27 +1100, ASiF wrote: What is the output for this?
"%%%%"
sry typo
output would be:
%%
"Ravi" <ra**@despammed.com> wrote in message
news:bk********************************@4ax.com... I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
Yes, only after adding '\n' it will most certainly output %%, otherwise you
need fflush(stdout) to make it print %%
"Servé Laurijssen" <i@bleat.nospam.com> wrote in message
news:bo**********@news2.tilbu1.nb.home.nl... "Ravi" <ra**@despammed.com> wrote in message
news:bk********************************@4ax.com... I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
Yes, only after adding '\n' it will most certainly output %%, otherwise
you need fflush(stdout) to make it print %%
Or end the program? I believe open files are flushed and closed when the
program end.
I have a number of times run into this problem in Java, where buffers are
not flushed and files closed, unless one explicitly closes them. (Close
does flush, yes.) It doesn't seem like too much to ask to me.
-- glen
"Servé Laurijssen" <i@bleat.nospam.com> wrote in message news:<bo**********@news2.tilbu1.nb.home.nl>... "Ravi" <ra**@despammed.com> wrote in message
news:bk********************************@4ax.com... I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
Yes, only after adding '\n' it will most certainly output %%, otherwise you
need fflush(stdout) to make it print %%
Technically, the fflush is still insufficient to guarantee output of
the last line of a text stream. [However, it does typically address
the issue for consoles where it is a problem.]
--
Peter
On Sun, 9 Nov 2003 19:38:20 +0100, "Servé Laurijssen"
<i@bleat.nospam.com> wrote: "Ravi" <ra**@despammed.com> wrote in message
news:bk********************************@4ax.com.. . I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
Yes,
When you say "yes" are you saying that it is implementation
dependent?
only after adding '\n' it will most certainly output %%, otherwise you
need fflush(stdout) to make it print %%
--
main(){char s[37]="CSbwjAjocpy/mw!PS!sbwjAeftqbnnfe/dpn";
int i;for(i=0;i<36;putchar(s[i++]-1));return 0;}
Greetings.
In article <j7********************************@4ax.com>, Ravi wrote: On Sun, 9 Nov 2003 19:38:20 +0100, "Servé Laurijssen"
<i@bleat.nospam.com> wrote:
"Ravi" <ra**@despammed.com> wrote in message
news:bk********************************@4ax.com. .. I hope this is not a FAQ.
printf("%%%%");
What is the output for this? Is it implementation dependent?
Yes,
When you say "yes" are you saying that it is implementation
dependent?
Yes, he is. (Given that there was only one yes-no question in your
original post, it's difficult to fathom what other interpretation one
could give this answer.)
--
_
_V.-o Tristan Miller [en,(fr,de,ia)] >< Space is limited
/ |`-' -=-=-=-=-=-=-=-=-=-=-=-=-=-=-= <> In a haiku, so it's hard
(7_\\ http://www.nothingisreal.com/ >< To finish what you
"Ravi" <ra**@despammed.com> wrote in message
news:j7********************************@4ax.com... printf("%%%%");
What is the output for this? Is it implementation dependent?
Yes,
When you say "yes" are you saying that it is implementation
dependent?
yes, but not in the manner you expected I guess. %% will print one % with
printf, but it's possible that nothing is printed if you omit the \n This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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