how to initialize a structure

[Ramprasad A Padmanabhan]

I have a simple structure defined like this

struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
};
typedef struct userid user;
Now I want to define a user array and initialize it

I tried something like this but doesnt work

user *list[] = {
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};
Is there a way I can initialize this array while its declaration.

Thanks
Ram

[Jirka Klaue]

Ramprasad A Padmanabhan wrote:

I have a simple structure defined like this

struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
};
typedef struct userid user;

Now I want to define a user array and initialize it

I tried something like this but doesnt work

user *list[] = { ^
Drop this.
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};

Is there a way I can initialize this array while its declaration.

struct userid {
char uid[MAXUIDLENGTH];
int insize, outsize;
} list[] = {
{"user1", 10, 20},
{"user2", 0, 20},
{"user3", 11, 2}
};

Jirka

[Irrwahn Grausewitz]

Ramprasad A Padmanabhan <ra*******@netcore.co.in> wrote:

<snip>

I tried something like this but doesnt work

user *list[] = {
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};

Drop the spurious * and you'll be fine.

Regards
--
Irrwahn
(ir*******@freenet.de)

[Jens.Toerring]

Ramprasad A Padmanabhan <ra*******@netcore.co.in> wrote:

I have a simple structure defined like this struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
};
typedef struct userid user; Now I want to define a user array and initialize it I tried something like this but doesnt work user *list[] = {
This declares an array of *pointers* to such structures, but not
an array of structures. I guess you should get rid of the '*' in
front of 'list'.
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};

And that's how you would initialize an array of structures. That's
ok when you remove the '*'.
Regards, Jens
--
_ _____ _____
| ||_ _||_ _| Je***********@physik.fu-berlin.de
_ | | | | | |
| |_| | | | | | http://www.physik.fu-berlin.de/~toerring
\___/ens|_|homs|_|oerring

[Kevin Bracey]

In message <bn*************@ID-166953.news.uni-berlin.de>
Ramprasad A Padmanabhan <ra*******@netcore.co.in> wrote:

I have a simple structure defined like this

struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
};
typedef struct userid user;
Now I want to define a user array and initialize it

I tried something like this but doesnt work

user *list[] = {
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};
Is there a way I can initialize this array while its declaration.

You can make list an array of "user"s rather than an array of "user *"s,
as others have suggested. Alternatively, if you really do want an array of
pointers, in C99 you can do it with compound literals:

user *list[] = {
&(user) {"user1",10,20},
&(user) {"user2",0,20},
&(user) {"user3",11,2}
};

--
Kevin Bracey, Principal Software Engineer
Tematic Ltd Tel: [phone]
182-190 Newmarket Road Fax: [phone]
Cambridge, CB5 8HE, United Kingdom WWW: http://www.tematic.com/

[Dan Pop]

In <bn*************@ID-166953.news.uni-berlin.de> Ramprasad A Padmanabhan <ra*******@netcore.co.in> writes:

I have a simple structure defined like this

struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
};
typedef struct userid user;
Don't typedef struct's, unless you have a *good* reason for doing it.
Saving a few keystrokes in declarations doesn't count as a good reason.

All you can achieve with gratuitous typedef's is render the code less
readable.
Now I want to define a user array and initialize it

I tried something like this but doesnt work

user *list[] = {
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};

Is there a way I can initialize this array while its declaration.

You need to learn how to declare things in C. Your initialiser is OK,
your declaration isn't. You're declaring an array of pointers to user,
NOT an array of user.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de

[pete]

Ramprasad A Padmanabhan wrote:

I have a simple structure defined like this

struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
};
typedef struct userid user;

Now I want to define a user array and initialize it

I tried something like this but doesnt work

user *list[] = {
{"user1",10,20},
{"user2",0,20},
{"user3",11,2}
};

Is there a way I can initialize this array while its declaration.

Program output:
C:\Program Files\DevStudio\SharedIDE\bin\Debug>new
user1, 10, 20
user2, 0, 20
user3, 11, 2

/* BEGIN new.c */

#include <stdio.h>

#define LIST \
{ \
{"user1",10,20}, \
{"user2", 0,20}, \
/* { "EXP",99,99}, \
*/ {"user3",11, 2} \
/* {"user4",10,20}, \
*/}
#define MAXUIDLENGTH (sizeof "user4")
#define STRUCTURES (sizeof array/ sizeof *array)

int main(void)
{
struct userid {
char uid[MAXUIDLENGTH];
int insize;
int outsize;
} array[] = LIST;
size_t structure;

for (structure = 0; structure != STRUCTURES; ++structure) {
printf("%s, %2d, %2d\n",
array[structure].uid,
array[structure].insize,
array[structure].outsize);
}
return 0;
}

/* END new.c */

--
pete