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calculating 64 bit hexadecimals

Hi all!

I have this big problem with making 64 bit hexa calculations and just found
out that windows calc CANNOT calculate more than 32 BIT!!! Does anybody know
of a reliable calculator to make double or long double hexadecimal
calculations that I can use? I really don't want to have to spend 300 euros
for an HP calculator and there HAS to be something around that I can
download. I have been trying to find something through google but none the
software I downloaded was accurate enough.

THANXS...

Yodai
Nov 13 '05 #1
7 3078
Yodai wrote:
I have this big problem with making 64 bit hexa calculations and just found
out that windows calc CANNOT calculate more than 32 BIT!!! Does anybody know
of a reliable calculator to make double or long double hexadecimal
calculations that I can use? I really don't want to have to spend 300 euros
for an HP calculator and there HAS to be something around that I can
download. I have been trying to find something through google but none the
software I downloaded was accurate enough.


http://gcc.gnu.org/

#include <stdio.h>
int main(void)
{
long long a = 0xDEADBEEF007, b = 0xAFFEAFFEAFFE;
printf("%llx + %llx = %llx\n", a, b, a + b);
}

gcc -Wall -std=c99 -o yodai yodai.c

Jirka

Nov 13 '05 #2
Jirka Klaue <jk****@ee.tu-berlin.de> scribbled the following:
Yodai wrote:
I have this big problem with making 64 bit hexa calculations and just found
out that windows calc CANNOT calculate more than 32 BIT!!! Does anybody know
of a reliable calculator to make double or long double hexadecimal
calculations that I can use? I really don't want to have to spend 300 euros
for an HP calculator and there HAS to be something around that I can
download. I have been trying to find something through google but none the
software I downloaded was accurate enough.
http://gcc.gnu.org/ #include <stdio.h>
int main(void)
{
long long a = 0xDEADBEEF007, b = 0xAFFEAFFEAFFE;
printf("%llx + %llx = %llx\n", a, b, a + b);
} gcc -Wall -std=c99 -o yodai yodai.c


"Affe Affe Affe"? Is this some German secret chant for invoking monkeys?
=)

--
/-- Joona Palaste (pa*****@cc.helsinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
"A bee could, in effect, gather its junk. Llamas (no poor quadripeds) tune
and vow excitedly zooming."
- JIPsoft
Nov 13 '05 #3
In <bn**********@mamenchi.zrz.TU-Berlin.DE> Jirka Klaue <jk****@ee.tu-berlin.de> writes:
Yodai wrote:
I have this big problem with making 64 bit hexa calculations and just found
out that windows calc CANNOT calculate more than 32 BIT!!! Does anybody know
of a reliable calculator to make double or long double hexadecimal
calculations that I can use? I really don't want to have to spend 300 euros
for an HP calculator and there HAS to be something around that I can
download. I have been trying to find something through google but none the
software I downloaded was accurate enough.


http://gcc.gnu.org/

#include <stdio.h>
int main(void)
{
long long a = 0xDEADBEEF007, b = 0xAFFEAFFEAFFE;
printf("%llx + %llx = %llx\n", a, b, a + b);
}

gcc -Wall -std=c99 -o yodai yodai.c


Who says that if you use gcc -std=c99, the standard library installed on
the system will be automatically C99-conforming?

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de
Nov 13 '05 #4
Dan Pop wrote:
Jirka Klaue <jk****@ee.tu-berlin.de> writes:

....
http://gcc.gnu.org/

#include <stdio.h>
int main(void)
{
long long a = 0xDEADBEEF007, b = 0xAFFEAFFEAFFE;
printf("%llx + %llx = %llx\n", a, b, a + b);
}

gcc -Wall -std=c99 -o yodai yodai.c


Who says that if you use gcc -std=c99, the standard library installed on
the system will be automatically C99-conforming?


Nobody said it. One would hope so, though. Otherwise it would be quite
pointless to use -std=c99, wouldn't it?

Jirka

Nov 13 '05 #5
In <3F**************@ee.tu-berlin.de> Jirka Klaue <jk****@ee.tu-berlin.de> writes:
Dan Pop wrote:
Jirka Klaue <jk****@ee.tu-berlin.de> writes:

...
http://gcc.gnu.org/

#include <stdio.h>
int main(void)
{
long long a = 0xDEADBEEF007, b = 0xAFFEAFFEAFFE;
printf("%llx + %llx = %llx\n", a, b, a + b);
}

gcc -Wall -std=c99 -o yodai yodai.c


Who says that if you use gcc -std=c99, the standard library installed on
the system will be automatically C99-conforming?


Nobody said it. One would hope so, though. Otherwise it would be quite
pointless to use -std=c99, wouldn't it?


Precisely my point: it *is* pointless to use -std=c99 and expect code
using C99 *library* features to work. Proof:

mentor:~/tmp 11> cat test.c
#include <math.h>

int main()
{
return round(0);
}
mentor:~/tmp 12> gcc -std=c99 test.c -lm
Undefined first referenced
symbol in file
round /var/tmp/cc92eQ7s.o
ld: fatal: Symbol referencing errors. No output written to a.out
collect2: ld returned 1 exit status

Things get even worse if the C99 function is there, but with different
semantics (as is the case with certain snprintf and freopen
implementations).

-std=c99 is only providing support for certain C99 *language*
features, and even that support might be broken (see
http://gcc.gnu.org/gcc-3.0/c99status.html for details).

Expecting anything else from -std=c99 is downright foolish.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de
Nov 13 '05 #6
Mac
Yodai wrote:
I have this big problem with making 64 bit hexa calculations and just found
out that windows calc CANNOT calculate more than 32 BIT!!! Does anybody know
of a reliable calculator to make double or long double hexadecimal
calculations that I can use? I really don't want to have to spend 300 euros
for an HP calculator and there HAS to be something around that I can
download. I have been trying to find something through google but none the
software I downloaded was accurate enough.


Somehow, I don't have the OP's question on my news server so I'm replying
here.

This is totally off-topic, so no follow-ups please.

The version of windows calculator I have at work does support 64-bit data.
You have to select the quad-word radio selection to make it work.

I'm not at work now so I can't check the version.

Mac
--

Nov 13 '05 #7
On 22 Oct 2003 13:23:44 GMT, Da*****@cern.ch (Dan Pop) wrote:
#include <stdio.h>
int main(void)
{
long long a = 0xDEADBEEF007, b = 0xAFFEAFFEAFFE;
printf("%llx + %llx = %llx\n", a, b, a + b);
}

gcc -Wall -std=c99 -o yodai yodai.c


Who says that if you use gcc -std=c99, the standard library installed on
the system will be automatically C99-conforming?


Being that this is a std. C newsgroup, I saved the above (which is not
standard C, but hey....) The output was not what I expected.... (I
compiled on Turbo C++ 3.0 for DOS) I got:

f007 + dbee = affe

Why not display the full contents of a,b, and c? I know on Turbo C++
for DOS, a long int is supposed to be 32 bits.... (at least I was
almost positive....) But granted, not guarantees according to
standard.... As far as the above, I don't believe C has any standard
for a voided main program.... And main should return a value....
Nov 13 '05 #8

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