#defines

[Naren]

Hello,

int main(){
int i=2,j=3;

printf("%d %d",i,j);

#define i j
#define j i

printf("%d %d",i,j);

}

What is the ouput in both the cases

Could anyone explain which tokens are considered while preprocessing.

Is the succesive preprocessor token replaced

thaanx in advance

Rgds,
Naren.

[Martin Ambuhl]

Naren wrote:

Hello,

int main(){
int i=2,j=3;

printf("%d %d",i,j);

#define i j
#define j i

printf("%d %d",i,j);

}

What is the ouput in both the cases

[modulo some whitespace]

int main()
{
int i = 2, j = 3;
printf("%d %d", i, j);
printf("%d %d", i, j);
}

--
Martin Ambuhl

[Ben Pfaff]

"Naren" <na*************@in.bosch.com> writes:

#define i j
#define j i

Could anyone explain which tokens are considered while preprocessing.

The preprocessor won't expand a macro name from within its own
expansion. So i expands to j, which expands to i, which ends the
chain of expansions. Similarly for j.

[snippage]
--
"Some programming practices beg for errors;
this one is like calling an 800 number
and having errors delivered to your door."
--Steve McConnell