Can static member funcs be friends?

[Improving]

why doesnt A::func have access to a B objects internals?

#include<iostream>
using namespace std;
class A;
class B
{
friend class A;
int a;

public:
B(int b) : a(b)
{;}
};

class A
{
static void func(B* b)
{
cout<< b->a << endl;
}
};

int main()
{
B b(10);
A::func(&b);
cin.get();
return 0;
}

[Rolf Magnus]

Improving wrote:

#include<iostream>
using namespace std;
class A;
class B
{
friend class A;
int a;

public:
B(int b) : a(b)
{;}
};

class A
{
public:
static void func(B* b)
{
cout<< b->a << endl;
}
};

int main()
{
B b(10);
A::func(&b);
cin.get();
return 0;
}

[sat]

Yes , there is nothing wrong with your code. It should run fine, but for one
hiccup.

int main()

{
B b(10);
A::func(&b); // this is an error

func in class A is by default a private member.. (though it is static),
hence your program might have not compiled.
try putting it in public scope. I thnk the program should go thro' fine.

"Improving" <ru**@haydon449.plus.com> wrote in message
news:11**********************@z14g2000cwz.googlegr oups.com... why doesnt A::func have access to a B objects internals?

#include<iostream>
using namespace std;
class A;
class B
{
friend class A;
int a;

public:
B(int b) : a(b)
{;}
};

class A
{
static void func(B* b)
{
cout<< b->a << endl;
}
};

int main()
{
B b(10);
A::func(&b);
cin.get();
return 0;
}

[Bob Hairgrove]

On 6 Oct 2005 03:19:14 -0700, "Improving" <ru**@haydon449.plus.com>
wrote:

why doesnt A::func have access to a B objects internals?
It does ... but you need to make A::func() public in order to call it
from main().
#include<iostream>
using namespace std;
class A;
class B
{
friend class A;
int a;

public:
B(int b) : a(b)
{;}
};

class A
{
static void func(B* b)
{
cout<< b->a << endl;
}
};

int main()
{
B b(10);
A::func(&b);
cin.get();
return 0;
}

--
Bob Hairgrove
No**********@Home.com

[Improving]

OMFG what a plonker I am!