Using a loop to do this...

[snow.carriers]

Basically getting a five digit number with a long unsigned variable,
and making the output like this:
number is 63424
6
3
4
2
4

Using loops, does anyone know how to start this? I'm thinking of using
powers of 10, % and a while loop...

Thanks

[John Fullman]

[e-mail] wrote:

Basically getting a five digit number with a long unsigned variable,
and making the output like this:
number is 63424
6
3
4
2
4

Using loops, does anyone know how to start this? I'm thinking of using
powers of 10, % and a while loop...

Thanks

On the right track.
(63424 - 63420) / 1 = 4
(63420 - 63400) / 10 = 2
etc...

[snow.carriers]

Thanks, but how would you incorporate that into a while loop?

[Gaijinco]

> Using loops, does anyone know how to start this? I'm thinking of using

powers of 10, % and a while loop...

Does this helps?

unsigned long number;
cin >> number;

for(int times=0, dig=10000; times < 5; ++times, dig/=10){
cout << number/dig%10 << endl;

[Greg]

sn***********@gmail.com wrote:

Thanks, but how would you incorporate that into a while loop?

It seems odd that the implementation has to use a while loop. A
loopless solution is perfectly reasonable:

#include <iostream>

void PrintDigits(int num)
{
if (num > 9)
PrintDigits(num/10);

std::cout << num%10 << std::endl;
}

int main()
{
PrintDigits(12345);
}

Output:
1
2
3
4
5

Surely the above solution would work just as well for your purposes.

Greg