Non Null Terminated string

[Raghavendra Mahuli]

Hi,
Is there anything called Non Null Terminated string (may be in UTF or
something) i.e. a string which does not have a '\0' at the end to
terminate.
In that case how can the end be identified?

Thanks in advance

regards,

Raghu

[Yandos]

Raghavendra Mahuli napsal(a):

In that case how can the end be identified?

You will have to know exact length of the string if you don't want to
use null terminated string. In such case the information about length is
usually placed before the string (first four bytes).

Y.

[Raghavendra Mahuli]

Hi Yandos,

Ok, Thanks ..
But is it used a standard format like stl::string or roguewave string?

regards,
raghu
"Yandos" <fa******@fakeisp.cz> wrote in message
news:43**********@x-privat.org...

Raghavendra Mahuli napsal(a):

In that case how can the end be identified?

You will have to know exact length of the string if you don't want to
use null terminated string. In such case the information about length is
usually placed before the string (first four bytes).

Y.

[benben]

> Hi,

Is there anything called Non Null Terminated string (may be in UTF or
something) i.e. a string which does not have a '\0' at the end to
terminate.
In that case how can the end be identified?

Yes. Take a look at std::basic_string<> template and std::string and
std::wstring typedef's.

Ben

[Richard Herring]

In message <dg**********@ns2.fe.internet.bosch.com>, Raghavendra Mahuli
<ra************@in.bosch.com> writes

Hi,
Is there anything called Non Null Terminated string (may be in UTF or
something) i.e. a string which does not have a '\0' at the end to
terminate.
std::basic_string (and hence std::string and std::wstring) can contain
nulls and need not be terminated by one.
In that case how can the end be identified?

When constructing or assigning to it, by using the forms of the
constructor or the insert(), assign(), append() etc. functions which
take a pointer and a count, or two iterators. When obtaining its value,
by using the data() and size() functions.

--
Richard Herring