const char *&

[Marcin Kalicinski]

void f(const char *&text);

Is this a const reference to char * or a reference to const char *? And how
to write both of them?

thank you,
Marcin

[John Carson]

"Marcin Kalicinski" <ka****@poczta.onet.pl> wrote in message
news:Tr******************@newsfe4-win.ntli.net

void f(const char *&text);

Is this a const reference to char * or a reference to const char *?
And how to write both of them?

You read from right to left, so it is a reference to a pointer to const
char. All references are const in the sense that you cannot "reseat" them to
refer to a different object. Your only choices in the present context are
between

1. a reference to a pointer to const char, as above,

const char *&text

2. a reference to a const pointer to char, which is

char *const &text

3. a reference to a const pointer to const char, which is

const char *const &text

Note that const char in 1. and 3. is the same as char const

--
John Carson

[jefong]

1,const int * a=&b;
when "const" on the left "*",specifies a const variable that is
referenced by a.
2.int * const a=&b;
when "const" on the right "*",specifies a const pointer.

[Karl Heinz Buchegger]

je****@56.com wrote:

1,const int * a=&b;
when "const" on the left "*",specifies a const variable that is
referenced by a.
2.int * const a=&b;
when "const" on the right "*",specifies a const pointer.

What about

int const * a = &b;

?

The thing is: Your 'rule' is mighty complicated.
Much simpler:

const always works on the thing to its left.
Unless const is the leftmost specifier, in which case
it works on the thing immediatly to its right.

So, in

const int * a

the const works on the thing immediatly to its right:
It is the int, that is const

int * const a

const is not the leftmost specifier, thus it works on the thing
to its left: it is the pointer that is const.

int const * a

const is not the leftmost specifier, thus it works on the thing
to its left: it is the int that is const.
--
Karl Heinz Buchegger
kb******@gascad.at