illegal indirections

[Kev]

Greetings all :o)

Pardon if my quickie code isnt exactly right. This is the classic 'you cant
do that' reference to a reference problem:

I am trying to avoid passing the class itself around... and from using
pointers. To get around the problem here is what I did. I havent been able
to really test this throughly as Im not ready to use it. But I am not
receiving any compile errors.

myclass a;
function1(a);

function1(myclass &b)
{
function2(myclass &b);
}

function2(myclass *c)
{
}

In function1 am I passing a pointer to 'a' to function2... without making
any duplicates of it?

cheers

[Gianni Mariani]

Kev wrote:

Greetings all :o)

Pardon if my quickie code isnt exactly right. This is the classic 'you cant
do that' reference to a reference problem:

I am trying to avoid passing the class itself around... and from using
pointers. To get around the problem here is what I did. I havent been able
to really test this throughly as Im not ready to use it. But I am not
receiving any compile errors.

myclass a;
function1(a);

function1(myclass &b)
{
function2(myclass &b);
}

function2(myclass *c)
{
}

In function1 am I passing a pointer to 'a' to function2... without making
any duplicates of it?

Yes. c will be a pointer to a.

[Kev]

Gianni Mariani <gi*******@mariani.ws> wrote in news:4bOdneUlkaORop3eRVn-
[e-mail]:

Yes. c will be a pointer to a.

Thank you. :o)

[Old Wolf]

Kev wrote:

Greetings all :o)
myclass a;
function1(a);
You can't have non-declaration statements at file scope.
I'll assume that those 2 lines were in some function,
but the following code is back at file scope.

function1(myclass &b)
{
function2(myclass &b);
That's a syntax error. Perhaps you meant:

function2(&b);

which would do the same as function2(&a) instead of function1(a).
}

function2(myclass *c)
{
}

[Kev]

"Old Wolf" <ol*****@inspire.net.nz> wrote in news:1124160930.879273.28370
@g49g2000cwa.googlegroups.com:

function1(myclass &b)
{
function2(myclass &b);

That's a syntax error. Perhaps you meant:

function2(&b);

which would do the same as function2(&a) instead of function1(a).

Havent read posts here in about a week. Yes you are correct... which is how
it ended up in the end.

Thank you :o)

Now Im trying to figure out why a simple fout.close() would cause an access
error