Difference between initialisation and assignment?

[Andy Lomax]

Is there any difference between:

foo A = B;

and

foo A;
A = B;

Specifically, I have a case where B is a function call which returns a
templated class. The first case gives a syntax error, but the second
case works. It appears to work because the assignment calls a type
conversion operator for the templated class.

Thanks -

AL

[Karl Heinz Buchegger]

Andy Lomax wrote:

Is there any difference between:

foo A = B;

and

foo A;
A = B;

The first is initialization.
The second is assignment.

For intialization a constructor is used.
For assignment the op= is used.

--
Karl Heinz Buchegger
kb******@gascad.at

[Jai]

For intialization(foo A = B;) a copy constructor is used.
For assignment(A = B;) the op= is used.
Jai

[Earl Purple]

class A
{
private:
int m_x;
public:
A( int x ) : m_x( x )
{
}
};

A a1 = 1; // should compile because constructor is not explicit
A a2; a2=2; // error. A does not have default constructor.

class B
{
private:
int m_x;
public:
B( int x ) : m_x( x )
{
}
B() : m_x(0)
{
}
};

const B b1=1; // should compile
const B b2; b2=2; // error, cannot assign b2 because it's const

class C
{
private:
int m_x;
public:
explicit C( int x ) : m_x( x )
{
}
B() : m_x(0)
{
}
};

C c1 = 1; // error, implicit cast
C c2; c2 = 2; // also an error
C c3( 3 ); // correct

[Karl Heinz Buchegger]

Earl Purple wrote:

What is the point you are trying to make?

--
Karl Heinz Buchegger
kb******@gascad.at