instantiate an array of class

[Anthony]

Hello All,

Say I have a class foo, how can I instantiate say 5 of them and store
information about each in an array?
I am open to any other approach that may be useful. Thanks, help is
appreciated.
-Anthony

class foo
{
public:
int num;
foo(int val) : num(val) { }
}

int main (int argc, char ** argv)
{
int rval = 0;
foo f[5] = {1, 2, 3, 4 , 5};

for (int i = 0; i < sizeof(f) / sizeof(*f); i++)
cout << f[i].num << endl;

return rval;
}

[wittempj]

You could use a vector like:

#include <vector>

using namespace std;

class foo
{
public:
int num;
foo(int val) : num(val) { }

};

int main (int argc, char ** argv)
{
int rval = 0;

vector<foo> f;
for(int i = 0; i < 5; ++i)
{
foo x(i);
f.push_back(x);
}

return rval;
}

[Pete Becker]

Anthony wrote:

Say I have a class foo, how can I instantiate say 5 of them and store
information about each in an array?
I am open to any other approach that may be useful. Thanks, help is
appreciated.
You do it like this:

class foo
{
public:
int num;
foo(int val) : num(val) { }
}

int main (int argc, char ** argv)
{
int rval = 0;
foo f[5] = {1, 2, 3, 4 , 5};

for (int i = 0; i < sizeof(f) / sizeof(*f); i++)
cout << f[i].num << endl;

return rval;
}

What's the problem?

--

Pete Becker
Dinkumware, Ltd. (http://www.dinkumware.com)

[Jay Nabonne]

On Wed, 01 Jun 2005 19:01:59 +0000, Anthony wrote:

Hello All,

Say I have a class foo, how can I instantiate say 5 of them and store
information about each in an array?
I am open to any other approach that may be useful. Thanks, help is
appreciated.
-Anthony

class foo
{
public:
int num;
foo(int val) : num(val) { }
}

int main (int argc, char ** argv)
{
int rval = 0;
// You can do:
foo f[5] = {foo(1), foo(2), foo(3), foo(4), foo(5)};

for (int i = 0; i < sizeof(f) / sizeof(*f); i++)
cout << f[i].num << endl;

return rval;
}

It's helpful if the constructor takes multiple arguments.

- Jay

[Ron Natalie]

Pete Becker wrote:

Anthony wrote:

Say I have a class foo, how can I instantiate say 5 of them and store
information about each in an array?
I am open to any other approach that may be useful. Thanks, help is
appreciated.

You do it like this:

class foo
{
public:
int num;
foo(int val) : num(val) { }
}

int main (int argc, char ** argv)
{
int rval = 0;
foo f[5] = {1, 2, 3, 4 , 5};

for (int i = 0; i < sizeof(f) / sizeof(*f); i++)
cout << f[i].num << endl;

return rval;
}

What's the problem?

He forgot the semicolon after the class definition.

[Pete Becker]

Ron Natalie wrote:

He forgot the semicolon after the class definition.

Well, yes, but is that really what he's complaining about, or is it a
typo in the posted code?

--

Pete Becker
Dinkumware, Ltd. (http://www.dinkumware.com)

[Farhan]

I think his code is just fine.

"Pete Becker" <pe********@acm.org> wrote in message
news:H_********************@rcn.net...

Anthony wrote:

Say I have a class foo, how can I instantiate say 5 of them and store
information about each in an array?
I am open to any other approach that may be useful. Thanks, help is
appreciated.

You do it like this:

class foo
{
public:
int num;
foo(int val) : num(val) { }
}

int main (int argc, char ** argv)
{
int rval = 0;
foo f[5] = {1, 2, 3, 4 , 5};

for (int i = 0; i < sizeof(f) / sizeof(*f); i++)
cout << f[i].num << endl;

return rval;
}

What's the problem?

--

Pete Becker
Dinkumware, Ltd. (http://www.dinkumware.com)