Default Value while 'passing by reference'

[mufasa]

We know C++ supports functions that can carry default values as
follows:

someFunction(int a, int b, int c =20);

So calling someFunction(x,y) is perfectly legal!

However, if I need to information by reference, can initiate the
referenced variable to a default value?

Eg:

int main()
{
int a = 20;
int b, c;

int &r = a;

someFunction(b,c); // <-------------------- POSSIBLE??
someFunction(b,c,r);//<-------------------- This is allowed

}

someFunction(int x, int y, int& z = 30); //<-- WELL??
{
}

[Sharad Kala]

"mufasa" <so*****@gmail.com> wrote in message

We know C++ supports functions that can carry default values as
follows:

someFunction(int a, int b, int c =20);

So calling someFunction(x,y) is perfectly legal!

However, if I need to information by reference, can initiate the
referenced variable to a default value?

Eg:

int main()
{
int a = 20;
int b, c;

int &r = a;

someFunction(b,c); // <-------------------- POSSIBLE??
someFunction(b,c,r);//<-------------------- This is allowed

}

someFunction(int x, int y, int& z = 30); //<-- WELL??
There should be no semicolon at the end
{
}

This is not legal C++. You are binding a non const reference (z) to a
temporary object, which is illegal. It will work if you bind it to some
l-value.

int a = 30;

void
someFunction(int x, int y, int& z = a)
{
}

Sharad

[Rolf Magnus]

mufasa wrote:

We know C++ supports functions that can carry default values as
follows:

someFunction(int a, int b, int c =20);

So calling someFunction(x,y) is perfectly legal!

However, if I need to information by reference, can initiate the
referenced variable to a default value?
Yes.
int main()
{
int a = 20;
int b, c;

int &r = a;

someFunction(b,c); // <-------------------- POSSIBLE??
someFunction(b,c,r);//<-------------------- This is allowed

}

someFunction(int x, int y, int& z = 30); //<-- WELL??
Your function is missing a return type.
{
}

Make that:

void someFunction(int x, int y, const int& z = 30); //<-- WELL??
{
}

[Gianni Mariani]

mufasa wrote:

We know C++ supports functions that can carry default values as
follows: ....
someFunction(int x, int y, int& z = 30); //<-- WELL??
void someFunction(int x, int y, const int& z = 30) {
}

If you're passing a reference to a literal (30), does it make sense that
you can modify it ? The C++ standard says you can't.

G