Format of compiler generated derived destructor when base has 'virtual ~base() throw():"

[qazmlp]

I have a class like this:
class base
{
public:
virtual ~base() throw();
// Other members
};
Now, if I write a class like this:
class derived:public base
{
// Other members
};

What will/should be the format of the compiler-generated destructor for derived?

Will it be this:
- ~derived(); or
- virtual ~derived(); or
- virtual ~derived() throw();

[qazmlp]

Could anybody reply to this post? I would like to know what exactly
'C++ standard' mentions about this.

Thanks!

qa********@rediffmail.com (qazmlp) wrote in message
news:<db**************************@posting.google. com>...
I have a class like this:
class base
{
public:
virtual ~base() throw();
// Other members
};
Now, if I write a class like this:
class derived:public base
{
// Other members
};

What will/should be the format of the compiler-generated destructor for derived?

Will it be this:
- ~derived(); or
- virtual ~derived(); or
- virtual ~derived() throw();